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Stells [14]
3 years ago
6

50 POINTS PLZ HELP!!!

Mathematics
2 answers:
xenn [34]3 years ago
6 0

Answer:

Writing about two pages any topic that you want, such as story, project, event, idea, .etc.please Do not copy and paste from the Interne.

anyanavicka [17]3 years ago
3 0

Answer:

The number of orders in is equal to the number of orders out in month 4 (April). It appears the solution represents the time at which warehouse shipments caught up with order quantities.

Step-by-step explanation:

For this table to make any sense, we have to assume that the year started with 3 orders in January, and that one order was shipped in January. Then the number of orders was 1 or 2 each month after that, and the number of orders shipped per month was 2 each month after that. That is, the tables represent year-to-date totals of orders in and out.

Alternate Interpretation

If the numbers here are actual orders in and out in each of the listed months, it appears the warehouse is getting better at shipping orders. That is, they are increasing the shipment rate by 2 orders a month each month. They will eventually ship enough to cover the total number of orders in (total of 20 by April), but total shipments through April only amount to 16 orders.

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You had a coupon that made the price of a large pizza 13.00. For what percent off was the coupon?
fomenos

Answer:20% oofff

Step-by-step explanation:

100-(13*100/o)=z

o=original price

100-(13*100/16.25)=z

100-80=z

20%

answer is z%

7 0
2 years ago
How do i answer these?
Harrizon [31]
The Aon Center is taller. You just need to look at the place values, like 5 and 10. Which is bigger? the ten of course. 
5 0
3 years ago
There are big spenders among University of Alabama football season ticket holders. This data set Roll Tide!! shows the dollar am
Bas_tet [7]

Using the z-distribution, as we have a proportion, the 95% confidence interval is (0.2316, 0.3112).

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

  • \pi is the sample proportion.
  • z is the critical value.
  • n is the sample size.

In this problem, we have a 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so the critical value is z = 1.96.

We also consider that 130 out of the 479 season ticket holders spent $1000 or more at the previous two home football games, hence:

n = 479, \pi = \frac{130}{479} = 0.2714

Hence the bounds of the interval are found as follows:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2714 - 1.96\sqrt{\frac{0.2714(0.7286)}{479}} = 0.2316

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2714 + 1.96\sqrt{\frac{0.2714(0.7286)}{479}} = 0.3112

The 95% confidence interval is (0.2316, 0.3112).

More can be learned about the z-distribution at brainly.com/question/25890103

7 0
2 years ago
PLEASE HELP ASAP
muminat
Last month, she had 100.....this month, 30 new members joined and 10 cancelled....thats basically the same as saying 20 new members joined...so there are now 120 members...at 10 per subscription = 120(10) = $ 1200 <=
7 0
3 years ago
K=11LMN what is formula for M
Lelechka [254]
M= K/11LN  You just need to move everything away from the M side by using division.
7 0
2 years ago
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