Answer:20% oofff
Step-by-step explanation:
100-(13*100/o)=z
o=original price
100-(13*100/16.25)=z
100-80=z
20%
answer is z%
The Aon Center is taller. You just need to look at the place values, like 5 and 10. Which is bigger? the ten of course.
Using the z-distribution, as we have a proportion, the 95% confidence interval is (0.2316, 0.3112).
<h3>What is a confidence interval of proportions?</h3>
A confidence interval of proportions is given by:

In which:
is the sample proportion.
In this problem, we have a 95% confidence level, hence
, z is the value of Z that has a p-value of
, so the critical value is z = 1.96.
We also consider that 130 out of the 479 season ticket holders spent $1000 or more at the previous two home football games, hence:

Hence the bounds of the interval are found as follows:


The 95% confidence interval is (0.2316, 0.3112).
More can be learned about the z-distribution at brainly.com/question/25890103
Last month, she had 100.....this month, 30 new members joined and 10 cancelled....thats basically the same as saying 20 new members joined...so there are now 120 members...at 10 per subscription = 120(10) = $ 1200 <=
M= K/11LN You just need to move everything away from the M side by using division.