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2 years ago

7

What is the distance between the points (-3, 1) and (1, 3)?

1 answer:

Murrr4er [49]2 years ago

3 0

Answer:

4.47

Step-by-step explanation:

a^2+b^2=c^2

2^2+4^2=c^2

4+16=c^2

20=C^2

$\sqrt{20}$ = $\sqrt{c^2}$

4.47=c

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Leni [432]

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2 years ago

What is the equation of the line that passes through the point (5,3) and has a slope<br> of?

klio [65]

Answer:

slope=2

I think that you can use demos it is a calculator just put the point and you get the answer

7 0

2 years ago

Suppose line segment AB has one endpoint at A(0, 0). What are the coordinates of B if (5, 3) is 1/3 of the way from A to B?

prisoha [69]

Answer:

$B(x_2,y_2)= (20,12)$

Step-by-step explanation:

Given

$A = (0,0)$

$Ratio; m : n = 1 : 3$

$Point\ at\ 1 : 3 = (5,3)$

Required

Coordinates of B

This question will be answered using line ratio formula;

$(x,y) = (\frac{mx_2 + nx_1}{m + n},\frac{my_2 + ny_1}{m + n})$

In this case:

$(x,y) = (5,3)$

$(x_1,y_1) = (0,0)$

$m : n = 1 : 3$

Solving for $(x_2,y_2)$

$(x,y) = (\frac{mx_2 + nx_1}{m + n},\frac{my_2 + ny_1}{m + n})$ becomes

$(5,3) = (\frac{1 * x_2 + 3 * 0}{1 + 3},\frac{1 * y_2 + 3 * 0}{1 + 3})$

$(5,3) = (\frac{x_2 + 0}{4},\frac{y_2 + 0}{4})$

$(5,3) = (\frac{x_2}{4},\frac{y_2}{4})$

Comparing the right hand side to the left;

$\frac{x_2}{4} = 5$ -- (1)

$\frac{y_2}{4} = 3$ -- (2)

Solving (1)

$x_2 = 5 * 4$

$x_2 = 20$

Solving (2)

$y_2 = 3 * 4$

$y_2 = 12$

Hence;

$B(x_2,y_2)= (20,12)$

5 0

3 years ago

A projectile is fired into the air with an initial vertical velocity of 160 ft/sec from ground level. How many seconds later doe

djverab [1.8K]

The maximum height of the projectile is the maximum point that can be gotten from the projectile equation

The projectile reaches the maximum height after 5 seconds

The function is given as:

$\mathbf{h(t) = -16t^2 + 160t}$

Differentiate the function with respect to t

$\mathbf{h'(t) = -32t + 160}$

Set to 0

$\mathbf{h'(t) = -32t + 160 = 0}$

So, we have:

$\mathbf{-32t + 160 = 0}$

Collect like terms

$\mathbf{-32t =- 160 + 0}$

$\mathbf{-32t =- 160}$

Solve for t

$\mathbf{t = \frac{- 160}{-32}}$

$\mathbf{t = 5}$

Hence, the projectile reaches the maximum after 5 seconds

Read more about maximum values at:

brainly.com/question/6636648

8 0

2 years ago

Adult tickets to Space City amusement park cost x dollars. Children's tickets cost y dollars. The Garcia family bought 3 adult a

KengaRu [80]

let the number of adult tickets be x and the number of children tickets be y

3x + y = 164...equ(1)

2x + 3y = 174....equ(2)

multiplying equation 1 by 3

9x + 3y = 492

subtracting equation 2 from 1

7x = 318

x = 45.43 dollars

substituting the value of x into the equation

3(45.428) + y = 164

y = 164 - 3(45.428)

∴y = 27.71 dollars

8 0

3 years ago