Question

a right triangle has side lengths 3, 4, and 5 as shown below. Use these lengths to find sinL, tanL, cosL​

Answer 1

Answer:

Step-by-step explanation:

I like to remember the three trigonometric equations with the following mnemonic device: SOH CAH TOA

SOH = $sin(x) = \frac{opposite}{hypotenuse}$

CAH = $cos(x) = \frac{adjacent}{hypotenuse$

TOA = $tan(x) = \frac{opposite}{adjacent}$

The $opposite$ length is the side length that is directly across (or opposite) of the given angle.

The $adjacent$ length is the side length that is right next to the given angle (but not the hypotenuse).

For this case, $sin(L)$ is going to be the opposite side length over the hypotenuse, which is $\frac{3}{5}$.

$tan(L)$ is going to be the opposite side length over the adjacent side length, which is $\frac{3}{4}$.

$cos(L)$ is going to be the adjacent side length over the hypotenuse, which is $\frac{4}{5}$.