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Alborosie
3 years ago
11

A manufacturer of bottled tea runs a promotion, where consumers can win a free bottle of tea if the cap of the bottle says "Winn

er.” The manufacturer claims that 1 in 5 bottles is a winner. Jack really likes the tea and has noticed that the last 10 bottles he has bought has not had a winner. Suspecting the manufacturer’s claim is false, Jack decides to select 10 bottles of tea from 10 randomly selected stores. He is surprised again when none of the 10 bottles is a winner. Assuming the manufacturer’s claim is true, Jack simulates 100 values of selecting winners in 10 bottles. The dotplot displays these simulated proportions.
Using the dotplot and the proportion of winners in Jack’s sample, is there convincing evidence that the manufacturer’s claim is wrong?

Yes; because a proportion of 0 occurred 3 out of 100 times, the sample proportion of winners is statistically significant and there is convincing evidence that the manufacturer’s claim is false.
Yes; because a proportion of more than 0 occurred 97 out of 100 times, the sample proportion of winners is statistically significant and there is convincing evidence that the manufacturer’s claim is false.
No; because a proportion of 0 occurred 3 out of 100 times, the sample proportion of winners is not statistically significant and there is not convincing evidence that the manufacturer’s claim is false.
No; because a proportion more than 0 occurred 97 out of 100 times, the sample proportion of winners is not statistically significant and there is not convincing evidence that the manufacturer’s claim is false.
Mathematics
1 answer:
I am Lyosha [343]3 years ago
8 0

Answer:

A

Step-by-step explanation:

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The deck of a bridge is suspended 275 feet above a river. If a pebble falls off the side of the bridge, the height, in feet, of
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Answer:

Our equation for the height is:

y(t) = 275 - 16*t^2.

a) To find the average velocity between two times, t1 and t2, (where t2 > t1) the equation is:

AV = \frac{y(t2) - y(t1)}{t2 - t1}

Then:

i) t1 = 4s, t2 = 4s + 0.1s = 4.1s

The average velocity is:

AV = \frac{(275 - 16*4.1^2) - (275 - 16*4^2)}{4.1 - 4} = \frac{16(4^2 - 4.1^2)}{0.1} = -129.6

And the units will be ft/s, so the average speed is:

-129.6 ft/s

The minus sign is because te pebble is falling down.

ii)  t1 = 4s, t2 = 4s + 0.05s = 4.05s

The average velocity is:

AV = \frac{(275 - 16*4.05^2) - (275 - 16*4^2)}{4.05 - 4} = \frac{16(4^2 - 4.05^2)}{0.05} = -128.8

So the average speed is -128.9 ft/s

iii)  t1 = 4s, t2 = 4s + 0.01s = 4.01s

The average speed is:

AV = \frac{(275 - 16*4.01^2) - (275 - 16*4^2)}{4.01 - 4} = \frac{16(4^2 - 4.01^2)}{0.01} = -128.16

The average speed is -128.16 ft/s.

b) The instantaneous velocity of the pebble after 4 seconds can be obtained by looking at the velocity equation, that is the derivative of the height equation.

v(t) = dy(t)/dt.

v(t) = -2*16*t + 0

Then the velocity at t = 4s is:

v(4s) = -32*4 = -128

The instantaneous velocity at t = 4s is -128 ft/s.

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3 years ago
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