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oee [108]
3 years ago
5

9. Find the value of x. Round to the nearest degree.

Mathematics
1 answer:
Setler79 [48]3 years ago
3 0
I need more information to answer this
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Factor (x^2-3x-2) into a binomial... I keep getting (x-1)(x-2) but it's not right
meriva
Are you absolutely positive that those are the signs exactly as in the question? As far as I know, there isn't 2 numbers that add to -3 and multiply to -2, meaning you can't factor it
6 0
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Simplify -14x^3/x^3- 5x^4 where x=?
ki77a [65]

Step-by-step explanation:

\dfrac{-14x^3}{x^3-5x^4}\qquad\text{where}\ x^3-5x^4\neq0\\\\x^3-5x^4\neq0\qquad\text{distributive}\\\\x^3(1-5x)\neq0\iff x^3\neq0\ \wedge\ 1-5x\neq0\\\\x\neq0\ \wedge\ x\neq\dfrac{1}{5}\\\\\dfrac{-14x^3}{x^3(1-5x)}\qquad\text{cancel}\ x^3\\\\=\dfrac{-14}{1-5x}\qquad\text{where}\ x\neq\dfrac{1}{5}

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3 years ago
20 POINTS PLEASE HELP
Rom4ik [11]
What are the measurements of the container
8 0
3 years ago
Suppose we want to choose 2 colors, without replacement from 3 colors red blue and green how many ways can this be done in the o
andre [41]

The two colors can be chosen in 3 different ways.

<h3>In how many ways can we choose two colors?</h3>

If we have a set of N elements, the number of different sets of K elements (such that the order of the K elements does not matter) is:

C(N, K) = \frac{N!}{(N - K)!*K!}

In this case, we have 3 colors, so N=3, and we want to choose 2, then K=2.

Replacing that we get:

C(3, 2) = \frac{3!}{(3- 2)!*2!} = \frac{3*2*1}{1*2*1}  = 3

The two colors can be chosen in 3 different ways.

If you want to learn more about combinations:

brainly.com/question/11732255

#SPJ1

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2 years ago
What's the diameter plz help
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