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oee [108]
3 years ago
5

9. Find the value of x. Round to the nearest degree.

Mathematics
1 answer:
Setler79 [48]3 years ago
3 0
I need more information to answer this
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The reflection of a Quadrant II point is located in Quadrant I. Assuming no error was made, what kind of reflection occurred?
gizmo_the_mogwai [7]

Answer:

A reflection across the y- axis

Step-by-step explanation:

Under a reflection in the y- axis

a point (x, y) → (-x, y)

A point in the second quadrant (- x, y)

Under reflection in the y- axis is (x, y) ← point in first quadrant

3 0
3 years ago
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Find the circumference of a tire with diameter of 20 inches.​
sattari [20]

Answer:

Circumference of a 20 Inch Diameter Circle.

Step-by-step explanation:

62.832 inches

5′ 2.832″ feet and inches

1.5959 meters

159.59 centimeters

3 0
3 years ago
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The fraction 26/5 is between which two numbers​
gayaneshka [121]

Answer:

\huge\boxed{5,6}

Step-by-step explanation:

The fraction 26/5 can be simplified to 5 and 1/5, which is between the numbers 5 and 6.

Hope it helps :) and let me know if you want me to elaborate.

5 0
3 years ago
Which value of m will create a system of parallel lines with no solution? y=mx-6 8x-4y=12 A coordinate grid with one line labele
nydimaria [60]

Answer:

A system of parallel lines will be created where the two lines will never meet and have no common solution at a value of m = 2

Step-by-step explanation:

The equation of the given line is 8·x - 4·y = 12

Which gives;

8·x- 12= 4·y

y = 2·x - 3

Given that the line passes through the points (0, -3) and (1, -1), we have;

Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}

When (x₁, y₁) = (0. -3) and (x₂, y₂) = (1, -1), we have;

Slope, \, m =\dfrac{(-1)-(-3)}{1-(0)} = 2

y - (-3) = 2×(x - 0)

y = 2·x - 3 which is the equation of the given line

For the lines 8·x - 4·y = 12, which is the sane as y = 2·x - 3 and the line y = m·x  - 6 to have no solution, the slope of the two lines should be equal that is m = 2

Given that the line passes through the point (1.5, 0), we have;

y - 0 = 2×(x - 1.5)  

y = 2·x - 3...................(1)

For the equation, y = m·x  - 6, when m = 2, we have;

y = 2·x  - 6..................(2)

Solving equations (1) and (2) gives;

2·x - 3 = 2·x  - 6, which gives;

2·x - 2·x=  - 3 - 6

0 = 9

Therefore, a system of parallel lines will be created where the two lines will never meet and have no common solution at a value of m = 2.

4 0
3 years ago
If f(x)=(x+1)(x-2)(x-3) represents a student's displacement from school in
amm1812
A is the answer to your question
5 0
3 years ago
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