We know that
<span>In a right triangle
if A and B are complementary angles
cos A=sin B
therefore
if cos A=5/13
then sin B=5/13
the answer is
sin B=5/13</span>
Answer:

The exponent is 2.
Step-by-step explanation:
Remember multiplicity rules:
- If a factor has an odd multiplicity (e.g. it is raised to 1, 3, 5...) then it will cross the x-axis.
- If a factor has an even multiplicity (e.g. it is raised to 2, 4, 6...) then it will bounce off the x-axis.
At x=2, we have the factor (x-2).
From the graph, we can see that the graph bounces off at that point.
Hence, the multiplicity of (x-2) must be even.
Therefore, a possible exponent for the factor (x-2) is 2. Any even number will suffice.
Complement of an angle = 90° - x.
Supplement of the complement of an angle = 180 - (90 - x).
= 180 - 90 + x
= 90 + x
Supplement of the complement of an angle less the complement of an angle = (90 + x) - (90 - x)
= 90 + x - 90 + x
= 2x
Now, the quotient of the supplement of the angle and the number 3 is
.
It is given that supplement of the complement of an angle less the complement of an angle exceeds the quotient of the supplement of the angle and the number 3 by 73.
Therefore, 2x = 

Multiply both sides by 3.
6x = 180 - x + 219
= 399 - x
Add x to both sides.
6x + x = 399
7x = 399
Divide both sides by 7.
x = 57
Hence, the required angle = 57°.