Which angle is supplementary to ∠1?

To play his game, Charles must distribute 350 tokens, when there are 7 players. How many will he have to distribute for 11 playe

Rzqust [24]

First divide 350 with 7

350/7 = 50.

Each player gets 50 tokens.

Now there are 11 players.

Multiply 50 with 11

50 x 11 = 550

550 tokens are distributed for 11 players

hope this helps

4 0

3 years ago

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What is the midpoint of the line segment with endpoints of (-2,-2) and (4,6)?

slamgirl [31]

Answer:

option (d) is correct.

The mid points of the line segment whose ends points are (-2,-2) and (4,6) is (1,2)

Step-by-step explanation:

Given: end points of a line segment as (-2,-2) and (4,6)

We have to find the mid points of the line segment whose ends points are given.

Mid point formula is stated as ,

For a line having end points as $\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right)$ , the mid point can be calculated as,

$\mathrm{Midpoint\:of\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)$

Here,

$\left(x_1,\:y_1\right)=\left(-2,\:-2\right),\:\left(x_2,\:y_2\right)=\left(4,\:6\right)$

Substitute in mid point formula, we get,

$=\left(\frac{4-2}{2},\:\frac{6-2}{2}\right)$

Solving further , we get,

$=\left(1,\:2\right)$

Thus, the mid points of the line segment whose ends points are (-2,-2) and (4,6) is (1,2)

Thus, option (d) is correct.

6 0

3 years ago

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How to find the volume of a quarter-sphere?

Ganezh [65]

As the word suggests, a quarter-sphere is a quarter of a sphere, and thus the volume of a quarter-sphere is a quarter of the volume of the sphere.

The volume of a sphere is computed as

$\dfrac{4}{3} \pi r^3$

So, the volume of a quarter-sphere is

$\dfrac{1}{4}\cdot \dfrac{4}{3} \pi r^3 = \dfrac{1}{3} \pi r^3$

7 0

2 years ago

Find the midpoint of PQ<br><br> P(4 1/3, 3 1/6), Q(-2 1/5, 3 2/3)

Paha777 [63]

Answer:

$(1\frac{1}{15},3\frac{5}{12})$

Step-by-step explanation:

To find the midpoint, you must average the x's then average the y's.

So the x's are $4 \frac{1}{3}$ and $-2\frac{1}{5}$ .

The y's are $3\frac{1}{6}$ and $3\frac{2}{3}$ .

To find an average of a data with 2 elements you must add the two elements then take that sum and divide it by 2.

So this is what we will do with the x's then the y's.

So first x:

$\frac{4\frac{1}{3}+-2\frac{1}{5}}{2}$

Write as improper fractions:

$\frac{\frac{13}{3}+\frac{-11}{5}}{2}$

Division by 2 is the same as multiplying by 1/2:

$\frac{13}{6}+\frac{-11}{10}$

The least common multiple of 6 and 10 is 30. We will multiply first fraction by 5/5 and 3/3 for the second so we can have the same denominator.

$\frac{65}{30}+\frac{-33}{30}$

Now that the bottoms are the same we can write as one fraction:

$\frac{65+-33}{30}$

Simplify:

$\frac{32}{30}$

If you want the answer as a mix fraction like your question began as we can do that by first figuring out how many 30's are in 32 and what is the remainder of that division.

There is one 30 and 32 and so 32-30=2 is the remainder.

$1\frac{2}{30}$