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olga_2 [115]
3 years ago
12

Hey AnIdiotLul, can you help me on some math today?

Mathematics
2 answers:
docker41 [41]3 years ago
3 0

Answer:

who is AnIdiotLul?

ziro4ka [17]3 years ago
3 0

Answer:

Sure

Step-by-step explanation:

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Which linear equation can be derived from this proportion?
inn [45]

9514 1404 393

Answer:

  D.  2x - 6 = 5x - 45

Step-by-step explanation:

To make the linear equation, we can multiply the given equation by 5(x-3).

  \dfrac{x-9}{x-3}=\dfrac{2}{5}\\\\\dfrac{(x-9)(5)(x-3)}{(x-3)}=\dfrac{2(5)(x-3)}{5}\\\\5(x-9)=2(x-3)\qquad\text{looks like }\textit{cross multiply}\\\\5x-45=2x-6\qquad\text{use the distributive property; matches D.}

8 0
3 years ago
All of the following are defined terms except _____.<br> A.ray<br> B.angle<br> C.plane<br> D.segment
FromTheMoon [43]
A plane is an undefined term. =)
6 0
3 years ago
Read 2 more answers
Negative ten is no less than two times a number plus fourteen
creativ13 [48]
All you do is change signs write 2x minus 14 equals negative 10-14 equals four then you write 2x over two equals four over two then u write x equals negative two
5 0
3 years ago
What is the value of the y-coordinate of the solution to the system of equation 2x+y=8 and x-3y=-3
r-ruslan [8.4K]
1) 2x + y = 8                           2) x - 3y = -3
    y = -2x + 8                              y = -x - 3 / -3
y-coordinate: (0, 8)             x-coordinate: (-3, 0)
8 0
4 years ago
The proportion of households in a region that do some or all of their banking on the Internet is 0.31. In a random sample of 100
Alenkasestr [34]

Answer:

Approximate probability that the number of households that use the Internet for banking in a sample of 1000 is less than or equal to 130 is less than 0.0005% .

Step-by-step explanation:

We are given that let X be the number that do some or all of their banking on the Internet.

Also; Mean, \mu = 310/1000 or 0.31   and  Standard deviation, \sigma = 14.63/1000 = 0.01463 .

We know that Z = \frac{X-\mu}{\sigma} ~ N(0,1)

Probability that the number of households that use the Internet for banking in a sample of 1000 is less than or equal to 130 is given by P(X <= 130/1000);

 P(X <=0.13) = P( \frac{X-\mu}{\sigma}  <= \frac{0.13-0.31}{0.01463} ) = P(Z <= -12.303) = P(Z > 12.303)

Since this value is not represented in the z table as the value is very high and z table is limited to x = 4.4172.

So, after seeing the table we can say that this probability is approximately less than 0.0005% .

4 0
3 years ago
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