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Yanka [14]
2 years ago
6

Sin4u=2sin 2u cos 2u​

Mathematics
1 answer:
yKpoI14uk [10]2 years ago
4 0

Answer:

If you've learnt sin(A+B) = sinAcosB + cosAsinB,

sin(4u)

= sin(2u+2u)

= sin(2u)cos(2u) + cos(2u)sin(2u)

= 2 sin(2u) cos(2u).

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Construct a​ 95% confidence interval for the population​ mean, mu. Assume the population has a normal distribution. A random sam
aniked [119]

Given Information:  

Number of lithium batteries = n = 16

Mean life of lithium batteries = μ = 645 hours

Standard deviation of lithium batteries = σ = 31 hours

Confidence level = 95%  

Required Information:  

Confidence Interval = ?

Answer:  

CI = 628.5 \: to \: 661.5 \: hours

Step-by-step explanation:  

The confidence interval is given by

CI = \mu \pm t_{\alpha/2} (\frac{\sigma}{\sqrt{n}})

Where μ is the mean life of lithium batteries, σ is the standard deviation, n is number of lithium batteries selected, and t is the critical value from the t-table with significance level of

tα/2 = (1 - 0.95) = 0.05/2 = 0.025

and the degree of freedom is

DoF = n - 1 = 16 - 1 = 15

The critical value (tα/2) at 15 DoF is equal to 2.131 (from the t-table)

CI = 645 \pm 2.131(\frac{31}{\sqrt{16}})

CI = 645 \pm 2.131(7.75})

CI = 645 \pm 16.515

CI = 645 - 16.515 \: and \: 645 + 16.515

CI = 628.5 \: to \: 661.5 \: hours

Therefore, the 95% confidence interval is 628.5 to 661.5 hours

What does it mean?

It means that we are 95% confident that the mean life of 16 lithium batteries is within the interval of (628.5 to 661.5 hours)

6 0
3 years ago
How can I simplify (2x-3)^2?
Kisachek [45]

~~~(2x-3)^2\\\\=(2x-3)(2x-3)\\\\=(2x)(2x) - 3(2x) -3(2x) + 3(3)\\\\=4x^2 -6x -6x +9\\\\=4x^2 -12x +9

8 0
2 years ago
What’s Y Y - 7= 4(x+3)
r-ruslan [8.4K]

Answer:

y

=

−

√

4

x

+

19

Step-by-step explanation:

4 0
2 years ago
Right triangle ABC and its image, triangle A'B'C' are shown in the image attached.
AlladinOne [14]

Answer:

See explanation

Step-by-step explanation:

Triangle ABC ha vertices at: A(-3,6), B(0,-4) and (2,6).

Let us apply 90 degrees clockwise about the origin twice to obtain 180 degrees clockwise rotation.

We apply the 90 degrees clockwise rotation rule.

(x,y)\to (y,-x)

\implies A(-3,6)\to (6,3)

\implies B(0,4)\to (4,0)

\implies C(2,6)\to (6,-2)

We apply the 90 degrees clockwise rotation rule again on the resulting points:

\implies (6,3)\to A''(3,-6)

\implies (4,0)\to B''(0,-4)

\implies (6,-2)\to C''(-2,-6)

Let us now apply 90 degrees counterclockwise  rotation about the origin twice to obtain 180 degrees counterclockwise rotation.

We apply the 90 degrees counterclockwise rotation rule.

(x,y)\to (-y,x)

\implies A(-3,6)\to (-6,-3)

\implies B(0,4)\to (-4,0)

\implies C(2,6)\to (-6,2)

We apply the 90 degrees counterclockwise rotation rule again on the resulting points:

\implies (-6,-3)\to A''(3,-6)

\implies (-4,0)\to B''(0,-4)

\implies (-6,2)\to C''(-2,-6)

We can see that A''(3,-6), B''(0,-4) and C''(-2,-6) is the same for both the 180 degrees clockwise and counterclockwise rotations.

7 0
3 years ago
Find the solution of this system of equations 5x - 6y =-90 -10x - 6y =-90
ExtremeBDS [4]

5x - 6y = -90

-10 x - 6y = -90

Subtracting,

15x = 0

x = 0

y = -90/(-6) = 15

Answer: x=0, y=15


8 0
3 years ago
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