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sattari [20]
3 years ago
7

No more sad hacker noises....FREE HUGS!!!!!

Mathematics
1 answer:
Debora [2.8K]3 years ago
5 0

:( -_・)ᡕᠵ᠊ᡃ່࡚ࠢ࠘ ⸝່ࠡࠣ᠊߯᠆ࠣ࠘ᡁࠣ࠘᠊᠊ࠢ࠘

God may forgive your sins but i don’t

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Find the measure of the missing angles .
maw [93]

Answer:

d = 90°

e = 41°

f = 139°

Step-by-step explanation:

d + 90° = 180° (Angles in linear pair)

-> d = 180° - 90°

-> d = 90°

e = 41° (vertical angles)

f + 41° = 180° (Angles in linear pair)

-> f = 180° - 41°

-> f = 139°

5 0
2 years ago
Rewrite using distributive property. 7(2x + 6y)
GenaCL600 [577]

Answer:

14x+42y

Step-by-step explanation:

7(2x+6y)

14x+42y

6 0
3 years ago
Victoria and Georgetown are 36.2 mi from each other. How far apart would the cities be on a map that has a scale of 0.9 in 10.5
damaskus [11]

Answer:0.9 * (36.2/10.5) = 3.1 in

Step-by-step explanation:

I got an A <3

7 0
2 years ago
Help please!!!!!!!!!!!!!!!!!!!!!!!
Artist 52 [7]

9514 1404 393

Answer:

  a) $336

  b) $1036

Step-by-step explanation:

a) The interest is computed using the formula ...

  I = Prt

where P is the amount invested at rate r for t years.

  I = $700·0.08·6 = $336

The interest earned is $336.

__

b) The balance of the account is the sum of the original amount and the interest earned:

  balance = $700 +336 = $1036

The balance of the account is $1036.

5 0
3 years ago
Two types of coins are produced at a factory: a fair coin and a biased one that comes up heads 60 percent of the time. We have o
liraira [26]

Answer:

i) 0.1% probability that if the coin is actually fair, we reach a false conclusion.

ii) 0.05% probability that if the coin is actually unfair, we reach a false conclusion

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

Fair coin:

Comes up heads 50% of the time, so p = 0.5

1000 trials, so n = 1000

So

E(X) = np = 1000*0.5 = 500

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{1000*0.5*0.5} = 15.81

If the coin lands on heads 550 or more times, then we shall conclude that it is a biased coin.

(i) If the coin is actually fair, what is the probability that we shall reach a false conclusion?

This is the probability that the number of heads is 550 or more, so this is 1 subtracted by the pvalue of Z when X = 549.

Z = \frac{X - \mu}{\sigma}

Z = \frac{549 - 500}{15.81}

Z = 3.1

Z = 3.1 has a pvalue of 0.9990

1 - 0.9990 = 0.001

0.1% probability that if the coin is actually fair, we reach a false conclusion.

(ii) If the coin is actually unfair, what is the probability that we shall reach a false conclusion?

Comes up heads 60% of the time, so p = 0.6

1000 trials, so n = 1000

So

E(X) = np = 1000*0.6 = 600

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{1000*0.6*0.4} = 15.49

If the coin lands on less than 550 times(that is, 549 or less), then we shall conclude that it is a biased coin.

So this is the pvalue of Z when X = 549.

Z = \frac{X - \mu}{\sigma}

Z = \frac{549 - 600}{15.49}

Z = -3.29

Z = -3.29 has a pvalue of 0.0005

0.05% probability that if the coin is actually unfair, we reach a false conclusion

5 0
3 years ago
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