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3 years ago

Can someone pleaseeee help and if you’re correct i’ll give brainliest

Mathematics

1 answer:

balandron [24]3 years ago

8 0

Answer:

the first one

Step-by-step explanation:

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1 + 1 + 1 1/4 + 1 1/2 + 1 1/2 =

Cerrena [4.2K]

Answer: 6.25 or 6 $\frac{1}{4}$

Step-by-step explanation:

Lets do a pro gamer move and convert all fractions to decimals.

We now have 1+1+1.25+1.5+1.5.

From there on we simply do addition.

1+1+1.25+1.5+1.5=6.25

We get 6.25 or 6 $\frac{1}{4}$

4 0

3 years ago

Read 2 more answers

During a promotional weekend a state fair gives a free admission to every 175th Person who enters the fair on Saturday there wer

emmasim [6.3K]

Answer:

Step-by-step explanation:

If every 175th person gets free admission, that means

175th

175 * 2 = 350th

175 * 3 = 525th

person gets free admission and so on...

This basically means "how many 175s are there is 6742 (for first day) and 5487 (for 2nd day)?"

We would need to divide and see the WHOLE number, not the fractional(decimal) amount remaining. So

1st Day:

6742/175 = 38.53

This means 38 people will get free admission

2nd Day:

5487/175 = 31.35

This means 31 people will get free admission

In the 2 days, total of 38 + 31 = 69 people will get free admission

8 0

3 years ago

Which of the following is equal to [(x^2y^3)^-2/(x^6y^3z)^2]^-3

lara [203]

Answer:

A,B,D

Step-by-step explanation:

right on edge

4 0

3 years ago

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Helpppppppppppppppppp

topjm [15]

Answer:

Step-by-step explanation:

The question has no division answer. That makes C and D incorrect.

A for some reason is backwards. It makes no sense to use that. You are left with B. The reason A or B is correct is that the burn of calories must get larger with an increase in hours.

7 0

3 years ago

In 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams.

jekas [21]

Answer:

1,805 kg.

Step-by-step explanation:

We have been given that in 2010, the world's largest pumpkin weighed 1,810 kilograms. An average-sized pumpkin weighs 5,000 grams. We are asked to find the how much the world's largest pumpkin weighs than an average pumpkin.

First of all, we will convert the weight of average pumpkin in kilograms by dividing 5,000 by 1000 as 1 kg equals 1,000 gm.

$\text{The weight of average pumpkin}=\frac{5000\text{ gm}}{\frac{\text{1000 gm}}{\text{ 1 kg}}}$

$\text{The weight of average pumpkin}=5000\text{ gm}\times \frac{\text{ 1 kg}}{\text{1000 gm}}$

$\text{The weight of average pumpkin}=5\text{ kg}$

Now, we will subtract the weight of average pumpkin from world's largest pumpkin's weight.

$1,810\text{ kilograms}-5\text{ kilograms}=1,805\text{ kilograms}$

Therefore, the 2010 world-record pumpkin weighs 1,805 kilograms more than an average-sized pumpkin.

3 0

4 years ago

Read 2 more answers