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2 years ago

Simplify: 8x -10x + x

Mathematics

2 answers:

wlad13 [49]2 years ago

4 0

Answer

-x

Step-by-step explanation:

8x - 10x = 2x

2x + x = -1x

scoray [572]2 years ago

3 0

Answer:

Step-by-step explanation:

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Jake washes cars. On monday he washed 18 cars for $90. On tuesday he washed 9 cars for $45. On wednesday he washed 12 cars for $

chubhunter [2.5K]

Answer:

the rate of change is 5

Step-by-step explanation:

$90 / 18 cars = $5 per car

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That means the rate of change is 5 (5/1)

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21 is 25% of 84.......

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The mass of Jupiter is 1.898 × 10(27) kilograms, and the mass of Saturn is 5.68 × 10(26) kilograms. How much greater is Jupiter'

grandymaker [24]

Just subtract but take care of the power or else you can come up with wrong results !

so first make the power same ;

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for Saturn = 5.68×10(26)

so now subtract = (18.98-5.68) × 10(26)
= 13.3 × 10(26)

so the answer is 13.3 ×10(26)
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2 years ago

Find the area of a circle whose radius is<br> 52 km. Round to nearest tenth

goblinko [34]

Answer:

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3 years ago

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Given f: ℝ → ℝ and : ℝ → ℝ , for the following, find f(g(x)) and g(f(x)), and state the domain.

horrorfan [7]

Answer:

Remember, $(f\circ g)(x)=f(g(x))$ and the range of g must be in the domain of f.

$f(g(x))=f(x-1)=(x-1)^2-(x-1)=x^2-2x+1-x+1=x^2-3x+2$

$g(f(x))=g(x^2-x)=(x^2-x)-1=x^2-x-1$

The domain of f(g(x)) and g(f(x)) is the set of reals.

$f(g(x))=f(\sqrt{x}-2)=(\sqrt{x}-2)^2-x=\sqrt{x}^2-2*2*\sqrt{x}+2^2-x=-4\sqrt{x}+4$

$g(f(x))=g(x^2-x)=\sqrt{x^2-x}-2$

The domain of f(g(x)) is the set of nonnegative reals and the domain of g(f(x)) is the set of number such that $x^2-x\geq 0$

$f(g(x))=f(\frac{1}{x-1})=(\frac{1}{x-1})^2=\frac{1}{(x-1)^2}$

$g(f(x))=g(x^2)=\frac{1}{x^2-1}$

The domain of f(g(x)) is the set of reals except the 1 and the domain of g(f(x)) is the set of reals except the 1 and -1

$f(g(x))=f(\frac{1}{x-1})=\frac{1}{(\frac{1}{x-1}-1)}=\frac{1}{\frac{2-x}{x-1}}=\frac{x-1}{2-x}$

$g(f(x))=g(\frac{1}{x+2})=\frac{1}{(\frac{1}{x+2}-1)}=\frac{1}{\frac{-x-1}{x+2}}=\frac{x+2}{-x-1}$

The domain of f(g(x)) is the set of reals except 2, and the domain of g(f(x)) is the set of reals except -1.

$f(g(x))=f(log(2(x+3)))=f(log(2x+6))=log(2x+6)-1$

$g(f(x))=g(x-1)=log(2(x-1)+6)=log(2x+4)$

The domain of f(g(x)) is the set of nonnegative reals except -3. The domain of g(f(x)) is the set of nonnegative reals except -2.

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2 years ago