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2 years ago

A.50 B.100 C.40 D.180 E.45 F.130 G.155 H.90 I.135

Mathematics

2 answers:

stiks02 [169]2 years ago

5 0

Answer:

F. 130

hope this helped :)

wolverine [178]2 years ago

5 0

Answer:

F. 130

Step-by-step explanation:

Since you have a 180-degree angle, you can subtract it by 50. replace <2 by x

so, 50 + x = 180

180 - 50 = 130

The answer is 130 degree angle.

hope this helps and is right :)

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Find the area of the rectangle. (8x + 5) yards (8x - 5) yards

Zepler [3.9K]

Answer:

48x-5

Step-by-step explanation:

multiply

5*8x

to get

8x+40x-5

combine like term

48x-5

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1 year ago

3^x= 3*2^x solve this equation

kompoz [17]

In the equation

$3^x = 3\cdot 2^x$

divide both sides by $2^x$ to get

$\dfrac{3^x}{2^x} = 3 \cdot \dfrac{2^x}{2^x} \\\\ \implies \left(\dfrac32\right)^x = 3$

Take the base-3/2 logarithm of both sides:

$\log_{3/2}\left(\dfrac32\right)^x = \log_{3/2}(3) \\\\ \implies x \log_{3/2}\left(\dfrac 32\right) = \log_{3/2}(3) \\\\ \implies \boxed{x = \log_{3/2}(3)}$

Alternatively, you can divide both sides by $3^x$ :

$\dfrac{3^x}{3^x} = \dfrac{3\cdot 2^x}{3^x} \\\\ \implies 1 = 3 \cdot\left(\dfrac23\right)^x \\\\ \implies \left(\dfrac23\right)^x = \dfrac13$

Then take the base-2/3 logarith of both sides to get

$\log_{2/3}\left(2/3\right)^x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x \log_{2/3}\left(\dfrac23\right) = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(3^{-1}\right) \\\\ \implies \boxed{x = -\log_{2/3}(3)}$

(Both answers are equivalent)

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2 years ago

A pole that is 3.1m tall casts a shadow that is 1.29m long. At the same time, a nearby building casts a shadow that is 44.75m lo

Mkey [24]

Let b=height of building. By similar triangles we can say:

b/44.75=3.1/1.29

b=44.75*3.1/1.29

b≈107.54

b≈108 meters (to the nearest whole meter)

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3 years ago

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2 years ago

A group of 570 students were surveyed about the courses they were taking at their college with the following results:

garri49 [273]

Answer:

The number of students who took English and History, but not Math is 143.

Step-by-step explanation:

Denote the subject choices as follows:

M = a students was taking Math

E = a students was taking English

H = a students was taking History

The data provided is as follows:

N (M) = 257

N (E) = 282

N (H) = 323

n (M ∩ E) = 154

n (M ∩ H) = 171

n (E ∩ H) = 143

n (M ∩ E ∩ H) = 80

Consider the Venn diagram below.

From the provided data and the Venn diagram the value of the set E and H minus M is 143.

Thus, the number of students who took English and History, but not Math is 143.

7 0

2 years ago