Answer:
<h2>A. (0,1)</h2>
Step-by-step explanation:
The question lacks the e=required option. Find the complete question below with options.
Which of the following points does not belong to the quadratic function
f(x) = 1-x²?
a.(0,1) b.(1,0) c.(-1,0)
Let f(x) = 0
The equation becomes 1-x² = 0
Solving 1-x² = 0 for x;
subtract 1 from both sides;
1-x²-1 = 0-1
-x² = -1
multiply both sides by minus sign
-(-x²) = -(-1)
x² = 1
take square root of both sides;
√x² = ±√1
x = ±1
x = 1 and x = -1
when x = 1
f(x) = y = 1-1²
y = 1-1
y = 0
when x = -1
f(x) = y = 1-(-1)²
y = 1-1
y = 0
Hence the coordinate of the function f(x) = 1-x² are (±1, 0) i.e (1, 0) and (-1, 0). The point that does not belong to the quadratic function is (0, 1)
Answer:
y
Step-by-step explanation:
12/25 that will be the answer so its the percent time always helps.
The sum of all angles (around the black dot) is 360°
All 5 angles (if you forget the red line) are the same; so each angle is 360°/5 = 72°
So Angle 1 is 72°
To find this you would divide 868cupcakes by 31boxes witches is 28cupcakes in each box
hope this helps good luck have a good nite hope u enjoy ur the rest of ur weekend
