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Tems11 [23]
3 years ago
14

Find the inflation rate from 1992 to 1993 . Assume that all prices have risen at the same rate as the CPI.

Mathematics
1 answer:
Zinaida [17]3 years ago
7 0

69,420

69,420

69,420

69,420

69,420

69,420

69,420

69,420

69,420

69,420

69,420

69,420|

69,420

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The set of ordered pairs of the form (x,y) shown below represent points on a graph for a direct variation.
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The answer is B y=2/3x
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The line contains the point (-2,-5) and is parallel to 2x-3y = 9.<br> What’s the equation
Karolina [17]

Answer:

y=(2x/3)-(11/3)

Step-by-step explanation:

https://www.emathhelp.net/calculators/algebra-1/parallel-and-perpendicular-line-calculator/

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3 years ago
The system of equations y=-2x+3 and y= x is graphed.What is the solution to the system of equations?
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(1,1) x=1 y=1

Step-by-step explanation:

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2 years ago
Which relation is a function?<br> Question 3 options:
EleoNora [17]

Answer:

A function is a relation in which each input has only one output. In the relation , y is a function of x, because for each input x (1, 2, 3, or 0), there is only one output y. x is not a function of y, because the input y = 3 has multiple outputs: x = 1 and x = 2.

I hope it's helpful!

8 0
3 years ago
Read 2 more answers
A grower believes that one in five of his citrus trees are infected with the citrus red mite. How large a sample should be taken
mihalych1998 [28]

Answer:

n=6147

Step-by-step explanation:

1) Notation and definitions

X=1 number of citrus trees that are infected with the citrus red mite.

n=5 random sample taken

\hat p=\frac{1}{5}=0.2 estimated proportion of citrus trees that are infected with the citrus red mite.

p true population proportion of citrus trees that are infected with the citrus red mite.

Me=0.01 represent the margin of error desired

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})

In order to find the critical values we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical values would be given by:

t_{\alpha/2}=-1.96, t_{1-\alpha/2}=1.96

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.01 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.2(1-0.2)}{(\frac{0.01}{1.96})^2}=6146.56  

And rounded up we have that n=6147

5 0
3 years ago
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