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AURORKA [14]
3 years ago
11

Instructions: Find the measure of the indicated angle to the nearest

Mathematics
1 answer:
SVETLANKA909090 [29]3 years ago
6 0

To find the indicated angle, we can use one of the three main trigonometric functions: sine, cosine, or tangent.

Remember: SOH-CAH-TOA

Looking from the angle, we know the adjacent side and the hypotenuse. Therefore, we should use cosine to solve.

cos(x) = 12/36

x = cos^-1(12/36)

x = 71 degrees

Hope this helps!

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Which number should each side of the equation 45x=845x=8 be multiplied by to produce the equivalent equation of x = 10?
Scilla [17]
2nd or 3rd option I hope I narrowed it down
3 0
3 years ago
If point OR=20 and PR=5, would OP=15?
mina [271]

Answer:

No

Step-by-step explanation:

If OR = 20,

PR = 5

<u><em>OP would be</em></u>:

=> 20+5

=> 25

3 0
3 years ago
Someone please help. I don’t understand these
WITCHER [35]

Answer: very too bad for you buddy study nexts time



Step-by-step explanation:


3 0
3 years ago
Using the quadratic formula to solve 4x^2-3x + 9=2x + 1 what are the values of x​
Alchen [17]

Answer:

x=5±√−103/8

Step-by-step explanation:

There's no real solutions

4x2−3x+9−(2x+1)=2x+1−(2x+1)

4x2−5x+8=0

x=−b±√b2−4ac/2a

x=−(−5)±√(−5)2−4(4)(8)/2(4)

x=5±√−103/8

8 0
3 years ago
Use the disk method or the shell method to find the volumes of the solids generated by revolving the region bounded by the graph
diamong [38]

Answer:

a) 8π

b) 8/3 π

c) 32/5 π

d) 176/15 π

Step-by-step explanation:

Given lines :  y = √x, y = 2, x = 0.

<u>a) The x-axis </u>

using the shell method

y = √x = , x = y^2

h = y^2 , p = y

vol = ( 2π ) \int\limits^2_0 {ph} \, dy

     = ( 2\pi ) \int\limits^2_0 {y.y^2} \, dy  

∴ Vol = 8π

<u>b) The line y = 2  ( using the shell method )</u>

p = 2 - y

h = y^2

vol = ( 2π ) \int\limits^2_0 {ph} \, dy

     = ( 2\pi ) \int\limits^2_0 {(2-y).y^2} \, dy

     = ( 2π ) * [ 2/3 * y^3  - y^4 / 4 ] ²₀

∴ Vol  = 8/3 π

<u>c) The y-axis  ( using shell method )</u>

h = 2-y  = h = 2 - √x

p = x

vol = (2\pi ) \int\limits^4_0 {ph} \, dx

     = (2\pi ) \int\limits^4_0 {x(2-\sqrt{x}  ) } \, dx

     = ( 2π ) [x^2 - 2/5*x^5/2 ]⁴₀

vol = ( 2π ) ( 16/5 ) = 32/5 π

<u>d) The line x = -1    (using shell method )</u>

p = 1 + x

h = 2√x

vol = (2\pi ) \int\limits^4_0 {ph} \, dx

Hence   vol = 176/15 π

attached below is the graphical representation of P and h

3 0
3 years ago
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