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Tanya [424]
3 years ago
15

PLEASE ANSWER!!! A certain transformation moves a line segment as follows: Pt. A (2, 1) moves to A' (2, -1) and Pt. B (5, 3) to

B' (5, -3). *
Rotation
Translation
Reflection
Dilation
Mathematics
2 answers:
erma4kov [3.2K]3 years ago
3 0

Answer:

Step-by-step explanation:

eee

Ronch [10]3 years ago
3 0
Both A and B would be Reflection. My explanation is bad but I did this before.
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You have two credit cards. One has a balance of $3,745.00 at a 6.25% apr and the other has a balance of $1,045.00 and is depende
Anika [276]

3745 x .0625 / 12  + 1045 x .1025 / 12 = 28.43.

$28.44 would be the closest.

Hope this helps & good luck. :)

4 0
4 years ago
Read 2 more answers
15. JAGUARUNDI A jaguarundi springs from a fence post to swat at a low flying bird.
sukhopar [10]

Answer:

The discriminant, -14.71 < 0, shows that there is no solution of the equation, h = -16·t² + 22.3·t + 2, at the line 'h = 10' feet, therefore, the Jaguarundi height as she springs will not be up to 10 feet and therefore she will not reach the bird

Step-by-step explanation:

From the question, the equation that models the Jaguarundi's height, 'h', ma be written approximately as follows;

h = -16·t² + 22.3·t + 2

Where;

t = The time (duration) in seconds

The discriminant of the equation a·x² + b·x + c = 0 is  b² - 4·a·c

When h = 10, we have;

10 = -16·t² + 22.3·t + 2

∴ 0 = -16·t² + 22.3·t + 2 - 10 = -16·t² + 22.3·t - 8

The discriminant of the given quadratic equation is given as follows;

The discriminant = 22.3² - 4 × (-16 × (-8)) = -14.71 < 0

Therefore, the function, h = -16·t² + 22.3·t + 2 has no real root at h = 10

The parabola does not reach or pass through the line h = 10 which is the height at which the bird is flying.

The Jaguarundi will not reach the bird flying at the height of 10 feet.

7 0
3 years ago
Read 2 more answers
HELP REALLY QUICK PLEASE
chubhunter [2.5K]

Answer:

The answer is 140

The yellow part which is shaded is 14x10 which equals 140

8 0
3 years ago
What time is 6 3/4 hours before 3:37a.m
Mrac [35]
10:12 pm 

6 hours before is 9pm
3/4=45/60
add 45+37=72-60=12=1+9=10:12
4 0
4 years ago
You drive 6.0 km at 50 km/h and then another 6.0 km at 90 km/h. your average speed over the 12 km drive will be
riadik2000 [5.3K]
V1=50km/h
v2=90km/h
s1=s2=6km
s=12km

The average speed over the 12 km drive:
v=s/t

The time needed to drive 12km will be:
t = t1+t2

t1=s1/v1, t2=s2/v2

t=s1/v1+s2/v2=(s1v2+s2v1)/(v1v2)

v=sv1v2/(s1v2+s2v1)=12*50*90/(6*50+6*90)=64,28 km/h

3 0
4 years ago
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