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2 years ago

Four less that the quotient of six and two

Mathematics

2 answers:

denis-greek [22]2 years ago

6 0

6/2 - 4

That should be your answer

san4es73 [151]2 years ago

3 0

(6/2) - 4 would be your answer

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Using the converse of Pythagorean Theorem and the law of sines and cosines solve the word problem.

Helga [31]

Answer:

It's the law of cosines

Step-by-step explanation:

law of cosines states that $c^{2} =a^{2} +b^{2} -2ab (cos(\alpha ))$

so we know that a = 7, b = 4, and alpha would be 135 degrees, so just plugging it in gets us 49+16-2*7*4*(-0.707) = 65 + 39.59 = 104.59

7 0

2 years ago

Can i have help on this q plz

Alexandra [31]

Answer:

14.8

Step-by-step explanation:

7.4 * 2 = 14.8.

hope this helps

8 0

1 year ago

Read 2 more answers

Simplify:0.3(x-2y)+0.5x-y

astraxan [27]

Answer:

0.3[x-2y] + 0.5x - y

Use the distributive property: a(b-c) = ab - ac

0.3x - 0.6y + 0.5x - y

Now, add/subtract all like terms

0.3x + 0.5x - 0.6y - y

0.8x - 1.6y

If you want, we can simplify that down further to:

0.8(x - 2y)

7 0

2 years ago

Read 2 more answers

Circle an expression and the variable you would substitute if for in each system y=2x <br>x+3y=14

Len [333]

X=2

Y=4

Multiply top so y values cancel out, so multiple top by -3. Y values cancel out. You combine top and bottom equations, x=2. Plug 2 in first equation for x. Y=4

7 0

2 years ago

A bug completes one lap along the edge of a circular planter of radius 11.7 cm in 13.91 s. How fast was it traveling? 1. 10.8518

IrinaK [193]

Answer:

8.5.28492 cm/s

Step-by-step explanation:

We are given that

Radius of circular planter=11.7 cm

Time taken by bug =13.91 s

We have to find the speed of bug.

We know that

Speed = $\frac{distance}{time}$

Distance traveled by bug = $2\pi r$

Distance traveled by bug = $2\times 3.14\times 11.7$

Because $\pi=3.14$

Speed of bug= $\frac{2\times 3.14\times 11.7}{13.91}=5.28224 cm/s$

Hence, speed of bug=5.2822 4 cm/s

Answer:8.5.28492 cm/s

8 0

2 years ago