Find the y-intercept then graph it.
which is :-
y=-2/3x+7/3
Answer:
So the decay percentage rate is of 70.8%
Step-by-step explanation:
An exponentil function has the following format:

In which c is a constant.
If a>1, we have that a = 1 + r and r is the growth rate.
If a<1, we have that a = 1 - r and r is the decay rate.
In this problem:
a = 0.292
A is lesser than 1, so r is the decay rate.
1 - r = 0.292
r = 1 - 0.292
r = 0.708
So the decay percentage rate is of 70.8%
Answer:
1
teasure chests of gold
Step-by-step explanation:
Since this is a problem of adding or subtracting fractions, you will have to do one or the other to solve. Since the pirates already had
of a treasure chest of gold and stole another
of a treasure chest to add to their collection, we need to add these two fractions:

In order to add or subtract fractions, you need to have a common denominator. Choosing a common denominator means looking for the lowest common multiple of the two denominators:
6: 6, 12, 18, 24
8: 8, 16, 24

Add them together: 
Answer:
they have been on vacation for 2 days i think
Step-by-step explanation:
1500-60=1440
1440-1080= 360
360÷180=2
hope this helps
Answer:
g(x) has a greater average rate of change
Step-by-step explanation:
From the given information, the table is:
<u>x | g(x)</u>
-1 7
0 5
1 7
2 13
From this table, we have g(0)=5 and g(2)=13
The average rate of change over [a,b] of g(x) is given by: 
This implies that on the [0,2]. the average rate of change is:

Also, we have that: f(0)=-4 and f(2)=-1.
This means that the average rate of change of f(x) on [0,2] is

Hence g(x) has a greater average rate of change on [0,2]