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sweet-ann [11.9K]
3 years ago
6

Felicity cuts 27 equal strips from a 6-yard spool of ribbon. Which expressions show the number of yards for one strip of ribbon

Mathematics
1 answer:
fiasKO [112]3 years ago
3 0

Answer:

2/9 yards

Step-by-step explanation:

Felicity cuts 27 equal strips from a 6-yard spool of ribbon. Which expressions show the number of yards for one strip of ribbon

From the above question:

27 equal strips of ribbon = 6 yards of spool

1 strip of ribbon = x yards

Cross Multiply

27 strips of ribbon × x yards = 6 yards × 1 strip of ribbon

x yards = 6/27

x yards = 2/9 yards

Therefore, for 1 strip of ribbon we need 2/9 yards

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The daily number of miles driven by a bus driver during a week are 50, 65, 78, 54, 53, 61, 79, and 78.
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C Both the mean and median are appropriate measures of center.

Step-by-step explanation:

5 0
2 years ago
The mathematics faculty at a college consists of 11 professors, 12 associate professors, 7 assistant professors, and 6 instructo
Nikolay [14]

Answer:

The probability of choosing a professor or an instructor is 47.22%.

Step-by-step explanation:

Given that the mathematics faculty at a college consists of 11 professors, 12 associate professors, 7 assistant professors, and 6 instructors, if a faculty member is selected, to find the probability of choosing a professor or an instructor the following calculation must be performed:

11 + 12 + 7 + 6 = 100

11 + 6 = X

36 = 100

17 = X

17 x 100/36 = X

1700/36 = X

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8 0
3 years ago
How would you solve these 2 maths problems?
sweet-ann [11.9K]

Answer:

see explanation

Step-by-step explanation:

(9)

Expand and simplify right side and compare coefficients of like terms on left side.

(x - 2)(x² + ax + b) + c

= x³ + ax² + bx - 2x² - 2ax - 2b + c

= x³ + x²(a - 2) + x(b - 2a) - 2b + c

compare with

x³ + 2x² - 3x + 4

x² terms

a - 2 = 2 ( add 2 to both sides )

a = 4

x terms

b - 2a = - 3 ← substitute a = 4

b - 8 = - 3 ( add 8 to both sides )

b = 5

constant terms

- 2b + c = 4 ← substitute b = 5

- 10 + c = 4 ( add 10 to both sides )

c = 14

Thus a = 4, b = 5 and c = 14

-------------------------------------------------

(10)

Since both functions cross the x- axis at - 2 then (- 2, 0) satisfies both, that is

f(- 2) = (-2)^{4} + a(- 2)³ + b(- 2)² + 36(- 2) + 144 = 0, that is

- 16 - 8a + 4b - 72 + 144 = 0

- 8a + 4b + 56 = 0

- 8a + 4b = - 56 → (1)

and

g(- 2) = (-2)^{4} + (a + 3)(- 2)³ - 23(- 2)² + (b + 10)(- 2) + 40 = 0, that is

- 16 - 8(a + 3) - 92 - 2(b + 10) + 40 = 0

- 16 - 8a - 24 - 92 - 2b - 20 + 40 = 0

- 8a - 2b - 112 = 0

- 8a - 2b = 112 → (2)

Subtract (1) from (2) term by term

- 6b = 168 ( divide both sides by - 6 )

b = - 28

Substitute b = - 28 into (2)

- 8a + 56 = 112 ( subtract 56 from both sides )

- 8a = 56 ( divide both sides by - 8 )

a = - 7

Thus a = - 7 and b = - 28

5 0
3 years ago
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