Differentiating an integral removes the integral.
f(x) = integral of dt/sqrt(t^3 + 2)
f'(x) = 1/sqrt(x^3 + 2)
f'(1) = 1/sqrt(1^3 + 2)
f'(1) = 1/sqrt(3) = sqrt(3)/3.
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Well if he’s burned 456.6 calories already and he needs to get to 500 then you would have to simply subtract 456.6 from 500
The equation: 500 - 456.6 = 43.4
Hope this helps!
x - 14 would be the equation
Does this help? Not really sure what you are asking.
Odd degree and negative leading coefient
means it goes from the top left to bottom right
goes infinitely down
as x aproaches infinity, y approaches neagtive infinity
Answer:
Likely
Step-by-step explanation:
