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Sedaia [141]
3 years ago
7

Is it bigger 0.000 01 or is it 0.001

Mathematics
2 answers:
Murljashka [212]3 years ago
8 0
The one with less zeros IN FRONT is bigger, but if the zeros are behind the number the most zeros would be bigger, so the answer is 0.001
lidiya [134]3 years ago
6 0
The number with less zeros is bigger because it is closer to 0, therefore it is closer to being a whole number. Hope this helped!
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a map of 5 inches represents 200 miles of actual distance suppose the distance between two cities on the map is 7 inches what is
iogann1982 [59]

Answer:

280 miles and the rule is multiply by 40

Step-by-step explanation:

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3 years ago
A triangle is such that the largest angle is 3 times the smallest angle. The third angle is 23 less than the largest angle. Find
Leokris [45]

largest angle:  3x

smallest angle:  x

third angle:  3x - 23

The sum of the angles of a triangle equals 180°

(3x) + (x) + (3x -23) = 180

7x - 23 = 180

7x = 203

x = 29

largest angle:  3x  = 3(29)  = 87

third angle:  3x - 23   = 3(29) - 23   = 87 - 23   = 64

Answer: 29°, 64°, 87°

4 0
3 years ago
Reggie has 195 trading cards. Each week, he purchases 16 more trading cards.
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192 + 195 = your answer! that is 387.
8 0
4 years ago
The length of a rectangle is eight more than twice the width. The perimeter is 64. Find the length and width
Rufina [12.5K]

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width 32 length 32

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Can someone help me
defon
Answer for problem 46 is choice A
Answer for problem 47 is choice B
Answer for problem 48 is choice E

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Work Shown

Problem 46
Equation 1: 3x+y = 17
Equation 2: x+3y = -1
Add equation 1 to equation 2 to get 4x+4y = 16. Divide every term by 4 to get x+y = 4. Then finally multiply both sides by 3 to get 3x+3y = 12
That shows why the answer is choice A

---------------------------------
Problem 47)

If y hours pass by, then y-(2/3)y=y/3 is the time value (2/3)y hours ago

So,
Distance = rate*time
d = r*t
d = x*(y/3)
d = (xy)/3
That's why the answer is choice B

---------------------------------
Problem 48)
Let L1,L2,L3 be the three lists where
L1 = {a1,a2,a3,...,ak} there are k scores here
L2 = {a1,a2,...,a10} there are 10 scores here
L3 = {a11,a12,...,ak} the remaining k-10 scores
S(L1) = sum of the scores in list L1
M(L1) = mean of L1 = 20 = S(L1)/k
M(L2) = mean of L2 = 15 = S(L2)/10
S(L1) = 20k
S(L2) = 150
S(L1) = S(L2)+S(L3)
M(L1) = [S(L2)+S(L3)]/k
20 = [150+S(L3)]/k
20k = 150+S(L3)
S(L3) = 20k-150
M(L3) = [S(L3)]/(k-10)
M(L3) = (20k-150)/(k-10)
So that shows why the answer is choice E
3 0
4 years ago
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