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2 years ago

What does 3w =30 mean a. 6 b.9 c.10 d.12

Mathematics

2 answers:

PolarNik [594]2 years ago

8 0

Answer:

w = 10

Step-by-step explanation:

3w = 30

Divide each side by 3

3w/3 = 30/3

w = 10

morpeh [17]2 years ago

7 0

Answer: Correct answer is c.10

Step-by-step explanation:

3w = 30 (It means you divide)

/3 /3 (You would divide both sides by 3)

w=10 (Then you're left with your answer w=10)

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*WILL GIVE BRAINLIST TO WHO EVER IS RIGHT!*

Scorpion4ik [409]

Answer:g(X)=2x^2-10

Step-by-step explanation:

If a function f(x) is translated 'c' units down then the equation of the translated function be f(x)-c

Here, f(x) is translated 2 units down to obtain g(x).

Hence, we have

g(x)=f(x)-2

=2x^2-8-2

=2x^2-10

8 0

2 years ago

A Simple random sample of 100 8th graders at a large suburban middle school indicated that 84% of them are involved with some ty

Setler [38]

Answer: a) (0.755, 0.925)

Step-by-step explanation:

Let p be the population proportion of 8th graders are involved with some type of after school activity.

As per given , we have

n= 100

sample proportion: $\hat{p}=0.84$

Significance level : $\alpha= 1-0.98=0.02$

Critical z-value : $z_{\alpha/2}=2.33$ (using z-value table)

Then, the 98% confidence interval that estimates the proportion of them that are involved in an after school activity will be :-

$\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

i.e. $0.84\pm (2.33)\sqrt{\dfrac{0.84(1-0.84)}{100}}$

i.e. $\approx0.84\pm 0.085$

i.e. $(0.84- 0.085,\ 0.84+ 0.085)=(0.755,\ 0.925)$

Hence, the 98% confidence interval that estimates the proportion of them that are involved in an after school activity : a) (0.755, 0.925)

3 0

3 years ago

Help meeeee!!!!!!! I’ll give you a cookie.

lianna [129]

Answer:

(-5,24)

Step-by-step explanation:

2f+3g-h

first we substitute in the numbers

2(-3)+3(1)-2

-6+3-2

-3-2

-5

Then again

2(5)+3(4)-(-2)

10+12+2

22+2

hope this helps!:)

7 0

3 years ago

1/8 + c = 4/5 what is c

ASHA 777 [7]

Answer:

27/40

Step-by-step explanation:

7 0

3 years ago

In order to estimate the average time spent on the computer terminals per student at a local university, data were collected fro

VladimirAG [237]

Answer:

Margin of error for a 95% of confidence intervals is 0.261

Step-by-step explanation:

Step1:-

Sample n = 81 business students over a one-week period.

Given the population standard deviation is 1.2 hours

Confidence level of significance = 0.95

Zₐ = 1.96

Margin of error (M.E) = $\frac{Z_{\alpha }S.D }{\sqrt{n} }$

Given n=81 , σ =1.2 and Zₐ = 1.96

Step2:-

 $Margin of error (M.E) = \frac{Z_{\alpha }S.D }{\sqrt{n} }$ 

 $Margin of error (M.E) = \frac{1.96(1.2) }{\sqrt{81} }$ 

On calculating , we get

Margin of error = 0.261

Conclusion:-

Margin of error for a 95% of confidence intervals is 0.261

4 0

3 years ago