Question

In circle J with \text{m} \angle HLK= 30^{\circ}m∠HLK=30

Answer 1

Answer:

The minor arc HK is 60 degrees

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

The inscribed angle is half that of the arc it comprises.

so

$m\angle HLK=\frac{1}{2}(arc\ HK)$

we have

$m\angle HLK=30^o$

substitute the given value

$30^o=\frac{1}{2}(arc\ HK)$

$arc\ HK=60^o$

Remember that the measure of the minor arc must be less than 180 degrees

therefore

The minor arc HK is 60 degrees