In circle J with \text{m} \angle HLK= 30^{\circ}m∠HLK=30
1 answer:
Answer:
The minor arc HK is 60 degrees
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
The inscribed angle is half that of the arc it comprises.
so
we have
substitute the given value
Remember that the measure of the minor arc must be less than 180 degrees
therefore
The minor arc HK is 60 degrees
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So you have a pole that is 10 feet tall that has a rope that goes from the top to the ground, the rope being 30 degrees to the ground... You can draw a right triangle using these dimensions. Now that you have a triangle, you look at where your 30degree angle is related to the side whose length you know and the side whose length you wish to find. The side you know is opposite from the 30 degrees while the side you want to find is the hypotenuse, for it goes down at an angle. You will use the opposite and hypotenuse sides, so, according to SOH CAH TOA, you will be using sin.
plug in those values and solve for your hypotenuse.
The easiest way to do this is if you knew the identities for special right triangles like the 30 60 90 triangles or the 45 45 90 triangles, but I showed you how to solve for your sides even if they're not special
plug in those values and solve for your hypotenuse.
The easiest way to do this is if you knew the identities for special right triangles like the 30 60 90 triangles or the 45 45 90 triangles, but I showed you how to solve for your sides even if they're not special