Answer: its b ;p
Step-by-step explanation:
To solve this problem, we have to apply mole-concept to this and we would need the molar mass of AlCl3. 2g of AlCl3 contains 9.034*10^21 molecules.
<h3>Number of Molecules in 2g of AlCl3</h3>
The molar mass of AlCl3 is given as 133.34g/mol
Data;
- mass = 2g
- molar mass = 133.34g/mol
Using the mole concept, we can equate the molar mass to the number of molecules present in the entity.
![133.34g = 6.023*10^2^3](https://tex.z-dn.net/?f=133.34g%20%3D%206.023%2A10%5E2%5E3)
If we equate this
![133.34g = 6.023*10^2^3\\2g = x molecules\\x = \frac{2*6.023*10^2^3}{133.34} \\x = 9.034*10^2^1 molecules](https://tex.z-dn.net/?f=133.34g%20%3D%206.023%2A10%5E2%5E3%5C%5C2g%20%3D%20x%20molecules%5C%5Cx%20%3D%20%5Cfrac%7B2%2A6.023%2A10%5E2%5E3%7D%7B133.34%7D%20%5C%5Cx%20%3D%209.034%2A10%5E2%5E1%20molecules)
From the calculations above, 2g of AlCl3 contains 9.034*10^21 molecules.
Learn more on mole concept here;
brainly.com/question/21150359
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$469.
376/4 = 94.
Then add that too 346
94 + 346 = 469
Answer:
A
Step-by-step explanation: