Answer:

Step-by-step explanation:
Length of the rectangle = 
Width of the rectangle = 
<u>Area of the rectangle:</u>
= Length × Width
![\displaystyle = \frac{9}{4} \times \frac{17}{5} \\\\= \frac{9 \times 17}{4 \times 5} \\\\= \frac{153}{20} \\\\= 7 \frac{13}{20} \ in.^2\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%3D%20%5Cfrac%7B9%7D%7B4%7D%20%5Ctimes%20%5Cfrac%7B17%7D%7B5%7D%20%5C%5C%5C%5C%3D%20%5Cfrac%7B9%20%5Ctimes%2017%7D%7B4%20%5Ctimes%205%7D%20%5C%5C%5C%5C%3D%20%5Cfrac%7B153%7D%7B20%7D%20%5C%5C%5C%5C%3D%207%20%5Cfrac%7B13%7D%7B20%7D%20%5C%20in.%5E2%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
<span>15<span>(<span>6−g</span>)</span></span><span>=<span><span>(15)</span><span>(<span>6+<span>−g</span></span>)</span></span></span><span>=<span><span><span>(15)</span><span>(6)</span></span>+<span><span>(15)</span><span>(<span>−g</span>)</span></span></span></span><span>=<span>90−<span>15g</span></span></span><span>=<span><span>−<span>15g</span></span>+<span>90</span></span></span>
Answer:
Step-by-step explanation:
Area of a trapezium is the average of the parallel sides times the distance between them.
If we subtract 15 units from each of the parallel sides, we end up with a triangle that has two sides of 8 units and one of 10 units. One of the 8 unit sides is the base and we need to find the height h which is perpendicular to this base.
Let the base be split into two segments, call one A, the other will be 8 - A
From Pythagoras.
10² - A² = h² = 8² - (8 - A)²
10² - A² = 8² - (8 - A)²
100 - A² = 64 - (64 - 16A + A²)
100 - A² = 64 - 64 + 16A - A²
100 = 16A
A = 6.25
h = √(10² - 6.25²)
h = √60.9375
A = ½(15 + 23)√60.9375
A = 148.31870246... ≈ 148.3 cm²
Both the train will meet after 36 minutes.
<h3>Concept:</h3>
- To find when both the train will meet again at the same time, we need to find the LCM of the frequency.
<h3>How to solve the given question?</h3>
- Frequency of express train = 9 minutes = 3 × 3
- Frequency of local train = 12 minutes = 2 × 2 × 3
- LCM = 2 × 2 × 3 × 3 = 36
Thus, both the train will meet after 36 minutes.
Learn more about LCM here:
brainly.com/question/21504246
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9.42 to the nearest tenth is 9.4!