I think B? I could be wrong
Answer:
x >=5 or x <=-3
Step-by-step explanation:
Solve an absolute value inequality
3|x-1| >= 12
Divide each side by 3
3/3|x-1| >= 12/3
|x-1| >= 4
Now there are two solutions
x-1 >= 4 or x-1 <= -4
Add 1 to each side
x-1+1 >= 4+1 or x-1+1 <= -4+1
x >=5 or x <=-3
Salvadors
u . t h th
3 . 3 0 0
3 . 3 4 5
3 . 3 5 0
salvador has the farthest distance.
Answer is a because a^-2 will be changed to 1/a^2
Hope that helps
