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kobusy [5.1K]
3 years ago
5

!!!URGENT!!! ANSWER QUICK I WILL GIVE BAINLIEST TO RIGHT ANSWER

Mathematics
1 answer:
solmaris [256]3 years ago
7 0

Answer:

25/9 = 2 7/9 = 2.7777777778

Step-by-step explanation:

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I need help on number 9
umka21 [38]

Answer:


Step-by-step explanation:

You used Pythagorean theroem which is correct as this does form a right triangle however 50 is the hypotenuse as the ladder is propped up against the wall. 30 would then be the height of the triangle and the base is unknown so...

50^{2} = 30^{2} + x^{2}

50 squared minus thirty squared gives 1600 so:

1600 = x^{2}

Therefore x is the square root of 1600 which is 40

7 0
3 years ago
Read 2 more answers
Please give me correct answer​
ikadub [295]

Answer:

answer of question number 1 is 2400, 2880, 3600 respectively.

answer of question number 2 is 1384 and 1680.

Step-by-step explanation:

100×24=2400

120×24=2880

150×24=3600

692×2=1384

420×4=1680

7 0
3 years ago
Z^2 - 12z= -11<br> Please help with this completing the square problem
Serjik [45]
Completing the square is pretty hard to explain for me but I'll try my best and hopefully you get what I'm saying in these steps.

First make sure your numbers are all on one side leaving zero on the other side:
z² - 12z + 11 = 0

The next step is the tricky part to explain. So look on the first number and the third number in the formula. The first number is 1z². What multiples equal 1? The only multiples would be one times one (1 x 1). So below z² write one over one like this:
z² - 12z + 11 = 0
\frac{1}{1}
But remember this is 1 x 1 and not actually division. For the + 11, think of all the multiples that equal positive 11. It can be 1 x 11 or -1 x -11 so put the first option in fraction form first to test. It doesn't matter which is on top or bottom.
So now you should be left with these:
\frac{1}{1}    \frac{11}{1}
Now you need to cross multiply here. 1 x 11 and 1 x 1. That will give you two positive numbers 1 and 11. In order to get your middle number from step 1 you need to add these two numbers and see if you will get -12. As you can see 11 + 1 doesn't equal -12 so now we need to use our second option -1 x -11. Our paper should now be changed to this:
\frac{1}{1} \frac{-11}{-1}
Cross multiply. 1 x -11 and 1 x -1. You get -11 and -1 as the result. Add both together and you get -12.
Now you just need to rearrange your fractions here. you can replace your 1 over one to z over z since z x z still equals your problem's z²:
\frac{1}{1}  \frac{-11}{-1} \\  \\  \frac{z}{z}  \frac{-11}{-1}  \\  \\  (z-11)(z-1)=0

Finally solve for z. Separate parentheses to two separate equations like this:
z - 11 = 0 and z - 1 = 0
z = 11 and z = 1
That should be your answer. Sorry if it still doesn't make sense still.
4 0
4 years ago
Which value of x is the solution set of the following inequality? -x+8&gt;6
spin [16.1K]

answer:

B. \:  2

explanation:

- x + 8 > 6 \\ subtract \: 8 \: from \: both \: sides \\  \\  - x >  - 2 \\ divide \: both \: sides \: by \:  - 1. \: since  \\   - 1 < 0 \: the \: inequality \: direction  \\  changed. \\  \\ x <  \frac{ - 2}{ - 1}  \\  \frac{ - 2}{ - 1}  = 2 \: can \: be \: simplified \: as \: 2 \: by \\ removing \: the \: negative \: from  \\ numerator \: and \: denominator.  \\  \\ x < 2

3 0
3 years ago
A crane lifts a pallet of concrete blocks 7ft from the back of a truck. The truck drives away and the crane lowers the pallet 11
Dmitrij [34]

Answer:

The position of the concrete relative to its initial position is 4ft behind its initial position

Step-by-step explanation:

Let us analyze the problem following the sequence of events.

First of all, the crane is initially 7 ft from the back of the truck.

Once the truck drives away, the crane lowers the concrete at 11 ft away from the back of the truck.

To get this distance relative to the initial position, we have to subtract the initial position from the final position of the concrete.

This will  be

11ft - 7ft = 4 ft

The position of the concrete relative to its initial position is 4ft behind its initial position

5 0
3 years ago
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