Answer:
The probability that a student is proficient in mathematics, but not in reading is, 0.10.
The probability that a student is proficient in reading, but not in mathematics is, 0.17
Step-by-step explanation:
Let's define the events:
L: The student is proficient in reading
M: The student is proficient in math
The probabilities are given by:
![P (L) = 0.81\\P (M) = 0.74\\P (L\bigcap M) = 0.64](https://tex.z-dn.net/?f=P%20%28L%29%20%3D%200.81%5C%5CP%20%28M%29%20%3D%200.74%5C%5CP%20%28L%5Cbigcap%20M%29%20%3D%200.64)
![P (M\bigcap L^c) = P (M) - P (M\bigcap L) = 0.74 - 0.64 = 0.1\\P (M^c\bigcap L) = P (L) - P (M\bigcap L) = 0.81 - 0.64 = 0.17](https://tex.z-dn.net/?f=P%20%28M%5Cbigcap%20L%5Ec%29%20%3D%20P%20%28M%29%20-%20P%20%28M%5Cbigcap%20L%29%20%3D%200.74%20-%200.64%20%3D%200.1%5C%5CP%20%28M%5Ec%5Cbigcap%20L%29%20%3D%20P%20%28L%29%20-%20P%20%28M%5Cbigcap%20L%29%20%3D%200.81%20-%200.64%20%3D%200.17)
The probability that a student is proficient in mathematics, but not in reading is, 0.10.
The probability that a student is proficient in reading, but not in mathematics is, 0.17
Answer:
60°.
Step-by-step explanation:
Answer : 2/3 or 0 R 6
Step-by-step explanation:
hope it helps
Answer:
y = - 1/2x + 5
Step-by-step explanation:
y = 2x – 6 slope = 2
Perpendicular line slope = -1/2
for (4 , 3) y = mx + b y = 3, x = 4, m = -1/2
b = y - mx = 3 - (-1/2) x 4 = 5
equation: y = - 1/2x + 5
Answer:
1 ) 10
2 ) 12
3 ) 12
4 ) 3
5 ) 10.19
6 ) 12.39
Step-by-step explanation:
by pythagorus theorm