Answer:
Numerator = 2(b^2+a^2) or equivalently 2b^2+2a^2
Denominator = (b+a)^2*(b-a), or equivalently b^3+ab^2-a^2b0-a^3
Step-by-step explanation:
Let
S = 2b/(b+a)^2 + 2a/(b^2-a^2) factor denominator
= 2b/(b+a)^2 + 2a/((b+a)(b-a)) factor denominators
= 1/(b+a) ( 2b/(b+a) + 2a/(b-a)) find common denominator
= 1/(b+a) ((2b*(b-a) + 2a*(b+a))/((b+a)(b-a)) expand
= 1/(b+a)(2b^2-2ab+2ab+2a^2)/((b+a)(b-a)) simplify & factor
= 2/(b+a)(b^2+a^2)/((b+a)(b-a)) simplify & rearrange
= 2(b^2+a^2)/((b+a)^2(b-a))
Numerator = 2(b^2+a^2) or equivalently 2b^2+2a^2
Denominator = (b+a)^2*(b-a), or equivalently b^3+ab^2-a^2b0-a^3
Answer:
{10,8}
Step-by-step explanation:
-3x + 4y = -62
4x + 5y = 0
let's eliminate the x
-3x + 4y = -62 | x -4 |
4x + 5y = 0 | x 3 |
12x - 16y = 248
12x + 15y = 0
-------------------- -
-31y = 248
y = 248/(-31) = 8
since you must do this proble with elimination, we cant use subtitution. so we repeat the way once more to find x (eliminate y)
-3x + 4y = -62 | x 5 |
4x + 5y = 0 | x 4 |
-15x + 20y = -310
16x + 20y = 0
-------------------- -
-31x = -310
x = -310/-31 = 10
Answer:
B. a pair of alternate exterior angles with measures of 130° and 50°
Step-by-step explanation:
Alternate exterior angles formed when two parallel lines are cut across by the same transversal line, are said to be congruent.
Therefore, a pair of alternate exterior angles cannot have different angle measures of 130° and 50°. Rather, both alternate exterior angles should be of equal measure of degree.
All other scenarios are possible result except option B: "a pair of alternate exterior angles with measures of 130° and 50°".
4 , 7 , 14 , 19 , 21 , 23 , 23 , 26 , 27 , 30
Step-by-step explanation:
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