What are the zeroes of the polynomial equation?
f(x) = x^2+9x+20
2 answers:
Zeroes are when f(x)=0
0=x^2+9x+20
factor
0=(x+4)(x+5)
set each to zero
x+4=0
x=-4
x+5=0
x=-5
zeroes are f(-5) and f(-4)
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Answer:
J's would be (-5,-4) if J was reflected over the line x=3.
here's the solution,
- n = 11
- a = 5 ( a = first term )
- d = 6 ( d = common difference )
we know,
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nth term ( 11th term ) = 65
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