Question

Factor the expression over the complex numbers. x^2+50

Answer 1

Let x^2+50=0 

solve for x first. 

x^2=-50 
x=+-√-50 

Write that as a complex number

x=+-√50i 

x=√50i    or     x=-√50i

Hope I helped :) 

Answer 2

Answer:

$(x+5\sqrt{2}i)(x-5\sqrt{2}i)$

Step-by-step explanation:

The factorization is in the form (x-a)(x-b) where a,b are zeros of the equation $x^{2} +50=0$.

$x^{2} =-50$

$x =\sqrt{-50}$

$x =\sqrt{50}i = 5\sqrt{2}i$ and $x =-\sqrt{50}i = -5\sqrt{2}i$

So, the factorization is $(x+5\sqrt{2}i)(x-5\sqrt{2}i)$