Answer:
The answer is B.
Step-by-step explanation:
The tripling time of population is 6 days and the population will be doubled in 3.5 days.
Given that the population of a bacteria is tripling in 6 days.
We have to find the tripling time of population and the time when the population will be doubled.
Suppose the population of bacteria in beginning be x.
The population of bacteria seems like arithmetic progression in which a =x, nth term =3x and n=6.
Aritmetic progression is a sequence which is having common difference.
nth term=a+(n-1)d
3x=x+(6-1)*d
3x-x=5d
2x=5d
d=2x/5
d=0.4x
So now we have to find the value of n where population will be 2x.
nth term=a+(n-1)d
put nth term=2x, a=x,d=0.4x
2x=x+(n-1)*0.4x
2x-x=(n-1)*0.4x
x/0.4x=n-1
2.5=n-1
n=2.5+1
n=3.5
Hence the population of bacteria willbe doubled after 3.5 days.
Learn more about arithmetic progressions at brainly.com/question/6561461
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Answer:
y - 5 = (3/2)(x - 2)
Step-by-step explanation:
If two lines are perpendicular, their slopes are negative reciprocals of one another.
The slope of 2x + 3y = 5 is found by solving this equation for y:
3y = -2x + 5, or y = (-2/3)x + 5/3.
Thus, the slope of the new line is the negative reciprocal of -2/3, which in turn comes out to 3/2.
Use the point-slope formula y - k = m(x - h):
Substituting the givens, we get y - 5 = (3/2)(x - 2)
Answer:
B, A, E, D
Step-by-step explanation:
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