Because arcsin or sin-1 only gives outputs that are in the first and fourth quadrant.
5pi / 6 is in the second quadrant.
Answer:
x = -2, proven below.
Step-by-step explanation:
3x + 7 + 2(4x+1) = 3(x-1) - 4
3x + 7 + 8x + 2 = 3x - 3 - 4
9 + 11x = 3x - 7
16 + 11x = 3x
16 = - 8x
-2 = x
Answer:
y = - 2x + (1/2 38) + 2 = y = -2x + 19x + 2 at any second and y = -2x^2 / 2 + 19/2 + 2/2 = <u>- x^2 + 19/2 + 2 </u>= - x (4) + 19/2(4) + 1 = -4+ 38 + 1 = 35 seconds
Step-by-step explanation: We see that 38-2ft = 36ft and y intercept = 2 and then -2x allows us to represent the starting point 2 as -2 (1) to allow a descend to our back to 0 for y one we find y intercept we know - x^2 is our simplified equation and an input into this to find the static and slowed descend back to 0 if you keep inputting at 5 and 6 you see the equation speed up Anyway at (4) substitute = 4 seconds we divide our simplified equation a = -x2 into a b c and divide each by 2 before working out the<u> </u><u>decline</u> of the equation<u> (as equation still represents all ascending and descending) </u>for the 4th second as the height was <u>already said to be at its max at 38 feet see equation in answer to find 4 as substitute for x </u>
Answer:
Step-by-step explanation:
The perimeter of a polygon is equal to the sum of all the sides of the polygon. Quadrilateral PTOS consists of sides TP, SP, TO, and SO.
Since TO and SO are both radii of the circle, they must be equal. Thus, since TO is given as 10 cm, SO will also be 10 cm.
To find TP and SP, we can use the Pythagorean Theorem. Since they are tangents, they intersect the circle at a 
, creating right triangles 
and 
.
The Pythagorean Theorem states that the following is true for any right triangle:
, where 
is the hypotenuse, or the longest side, of the triangle
Thus, we have:
Since both TP and SP are tangents of the circle and extend to the same point P, they will be equal.
What we know:
Thus, the perimeter of the quadrilateral PTOS is equal to 
