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Dafna11 [192]
3 years ago
7

triangle ABC is shown in the diagram. The links of the sides are in terms of the variable n, where n >4. complete the inquali

ty

Mathematics
2 answers:
drek231 [11]3 years ago
6 0

Answer:

M- B     M-A      M-C

Step-by-step explanation:

yw

Blababa [14]3 years ago
5 0

9514 1404 393

Answer:

  m∠B < m∠A < m∠C

Step-by-step explanation:

We can work with the triangle inequality to find that the side measures form a triangle when n > 5/4. For the given value of n ≥ 4, we don't need to be concerned with whether a triangle is formed or not.

For n = 4, the side lengths are ...

  a = 2(4) = 8

  b = (4) +3 = 7

  c = 3(4) -2 = 10

The longest side is opposite the largest angle, so the ordering of angles is ...

  m∠B < m∠A < m∠C

_____

The triangle inequality requires all of these inequalities be true:

  • a+b > c   ⇒   3n+3 > 3n-2 . . . always true
  • b+c > a   ⇒   4n+1 > 2n   ⇒   n > -1/2
  • c+a > b   ⇒   5n-2 > n+3   ⇒   n > 5/4

That will be the case for n > 5/4. The attached graph shows the sides and angles keep the same order for n > 3.

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\begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{3.5\% of a}}{\left( \cfrac{3.5}{100} \right)a}\implies 0.035a \\\\[-0.35em] ~\dotfill\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{4.5\% of 2a}}{\left( \cfrac{4.5}{100} \right)2a}\implies 0.045(2a)

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