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Shkiper50 [21]
3 years ago
10

Each side of a square potholder is 21 centimeters long. What is the area of the potholder?

Mathematics
1 answer:
Nuetrik [128]3 years ago
8 0

The answer is a 441 cm area

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1.
creativ13 [48]

If the diameter is 12 inches, the radius is 6 inches, because the radius is half the diameter.

Given the formula

A=\pi r^2

we have

A=36\pi

When you fold the circle in half, the resulting figure has half the area.

So, you start with a circle with area 36\pi

You fold it once and you have a semicircle with area 18\pi

You fold it twice and you have a quarter circle with area 9\pi

7 0
3 years ago
When x=12, y=8. Find x when y=12
Digiron [165]
<span>x : y is equal to 12 : 8. These can be reduced or cancelled down to 3 : 2 in the same proportions. Therefore, when y is 12, you have to multiply the smallest value y can be by 6, and must do the same to the smallest x value to retain the proportions. x = 18 when y = 12.</span>
6 0
3 years ago
A rectangle has a length of 20 inches. if its perimeter is 64 inches, what is the area?​
zzz [600]

Answer:

\boxed{ \bold{ \huge{ \boxed{  \sf 240 \:  {inches}^{2} }}}}

Step-by-step explanation:

Given,

Length of a rectangle = 20 inches

Perimeter of a rectangle = 64 inches

Area of a rectangle = ?

Let width of a rectangle be ' w ' .

<u>Fi</u><u>rst</u><u>,</u><u> </u><u>finding </u><u>the</u><u> </u><u>width</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>rectangle</u>

\boxed{ \sf{perimeter = 2(l + w)}}

plug the values

⇒\sf{64 = 2(20 + w)}

Distribute 2 through the parentheses

⇒\sf{64 = 40 + 2w}

Swap the sides of the equation

⇒\sf{40 + 2w = 64}

Move 2w to right hand side and change it's sign

⇒\sf{2w = 64 - 40}

Subtract 40 from 64

⇒\sf{2w = 24}

Divide both sides of the equation by 2

⇒\sf{ \frac{2w}{2}  =  \frac{24}{2} }

Calculate

⇒\sf{w = 12 \: inches}

Width of a rectangle ( w ) = 12 inches

<u>Now</u><u>,</u><u> </u><u>finding</u><u> </u><u>the</u><u> </u><u>area</u><u> </u><u>of </u><u>a</u><u> </u><u>rectangle</u><u> </u><u>having</u><u> </u><u>length</u><u> </u><u>of</u><u> </u><u>2</u><u>0</u><u> </u><u>inches</u><u> </u><u>and </u><u>width </u><u>of</u><u> </u><u>1</u><u>2</u><u> </u><u>inches</u>

\boxed{ \sf{area \: of \: rectangle = length \:  \times  \: \: width}}

plug the values

⇒\sf{area \: of \: rectangle =20 \times  12 }

Multiply the numbers : 20 and 12

⇒\sf{area \: of \: rectangle = 240 \:  {inches}^{2} }

Hence, Area of a rectangle = 240 inches²

Hope I helped !

Best regards!

7 0
3 years ago
Una deuda de $2.684.033 se debe amortizar en 5 años a la tasa de interes anual del 8%, con capitalización semestral. Calcular la
joja [24]

Answer:

english?

Step-by-step explanation:

6 0
2 years ago
Please can anyone help???
marta [7]

Answer:

x = -3, y = 0

Step-by-step explanation:

15 - 9 = 6

6 - 9 = -3

0 + 5 = 5

5 +5 = 10

8 0
3 years ago
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