Answer:
solution given:
B.
CE=2×2=4[base side is double to the line of mid point]
AB=15/2=7.5[b is a mid point]
m<AEC=75°[ corresponding angle]
5.
given:
BD=x+1
CE=x+10
we have
2BD=CE
2(x+1)=x+10
2x+2=x+10
2x-x=10-2
x=8
Given a right triangle with base, b and height, h with the angle opposide side h as θ.
The area of a triangle is given by
But,
Therefore, the area of the triangle in terms of <span>b and θ only is given by
</span>
Answer:
Rock D.
Step-by-step explanation:
We can assume that the force that the catapult does is always the same.
So, here we need to remember Newton's second law:
F = m*a
force equals mass times acceleration.
Where acceleration is the rate of change of the velocity.
So, if we want the rock to hit closer to the catapult, the rock must be less accelerated than rock B.
So, we can rewrite:
a = F/m
So, as larger is the mass of the rock, smaller will be the acceleration of the rock after it leaves the catapult (because the mass is in the denominator). So if we want to have a smaller acceleration, we need to choose a rock with a larger mass than rock B.
Assuming that the mass depends on the size, the only one that has a mass larger than rock B is rock D.
So we can assume that rock D is the correct option.
Answer:
The statistical power of a hypothesis test is the probability of detecting an effect, if there is a true effect present to detect. Power can be calculated and reported for a completed experiment to comment on the confidence one might have in the conclusions drawn from the results of the study.
I hope it's helpful!
