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3 years ago

15

The table below gives the price for different numbers of burgers. Do the numbers in the table represent a proportional relations

hip?

1 answer:

Masja [62]3 years ago

3 0

Yes it does.
18/6=21/7=24/8=27/9= 3

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store announced that their $500 appliances were on sale for $475 what is the percent discount on the appliances

Aleks04 [339]

Answer:

We are given that a store announced that their $500 appliances were on sale.

The price of the appliances after discount is $475.

We are required to find the percent discount on the appliances.

To find the percent discount, we have to use the below formula:

$\frac{(Actual-discounted)}{Actual} \times 100\%$

$\frac{500-475}{500}\times 100\%$

$\frac{25}{500} \times 100\%$

$0.05 \times 100\%$

$5\%$

Therefore, the percent discount on the appliances is 5%

6 0

4 years ago

Using the expansion for the binomial: ( x^3 − y^4 )^9 :The coefficient for the 6th term is

Lelechka [254]

Answer:

-126

Step-by-step explanation:

For the binomial expression $(a-b)^{n}$ the coefficient of $(r+1)^{th}$ term is given by ${n \choose r} \times -1^{(r)}$ .

We have to find the coefficient of 6th term in the binomial expansion of

$(x^{3}-y^{4})^{9}$ .

Hence n=9 and r=5

The coefficient of 6th term = ${9 \choose 5} \times (-1)^{5}$

= $-{9 \choose 5}$

= -126

8 0

3 years ago

Please answer! Worth 13 points

Arte-miy333 [17]

Answer: f(x) = 3.50x + 25

It would cost $53 to go on 8 rides

Step-by-step explanation:

8 0

3 years ago

Complete the square to solve the equation below. check all that apply.<br><br> x^2 + 8x - 1 = 19

Andreas93 [3]

X=-10,x=2.I hope this helps.

8 0

2 years ago

Read 2 more answers

Please Help me Check the image below!!!!!

WITCHER [35]

Answer:

First question:

The graph of $y=\frac{3-2x}{2-3x}$ has a vertical asymptote at x = $\frac{2}{3}$ and a horizontal asymptote at y = $\frac{2}{3}$

Second question:

The graph of equation $y=\frac{1-3x}{2+x}$ has a horizontal asymptote at y = -3 ⇒ C

Step-by-step explanation:

The vertical asymptotes will occur at the values of x for which make the denominator is equal to zero

The horizontal asymptotes will occur if:

Both polynomials are the same degree, divide the coefficients of the highest degree terms
The polynomial in the numerator is a lower degree than the denominator, the x-axis (y = 0) is the horizontal asymptote

First question:

∵ $y=\frac{3-2x}{2-3x}$

- To find the vertical asymptote equate the denominator by 0

to find the value of x

∵ The denominator is 2 - 3x

∴ 2 - 3x = 0

- Add 3x to both sides

∴ 2 = 3x

- Divide both sides by 3

∴ $\frac{2}{3}$ = x

∴ The graph has a vertical asymptote at x = $\frac{2}{3}$

To find the horizontal asymptote look at the highest degree of x in both numerator and denominator

∵ The denominator and the numerator has the same degree of x

- Divide the coefficient of x of the numerator and denominator

∵ The coefficient of x in the numerator is -2

∵ The coefficient of x in the denominator is -3

∵ -2 ÷ -3 = $\frac{2}{3}$

∴ The graph has a horizontal asymptote at y = $\frac{2}{3}$

The graph of $y=\frac{3-2x}{2-3x}$ has a vertical asymptote at x = $\frac{2}{3}$ and a horizontal asymptote at y = $\frac{2}{3}$

Second question:

The graph has a horizontal asymptote at y = -3

<em />

<em>means the numerator and the denominator has same highest degree and the coefficient of the highest degree in the numerator divided by the coefficient of the highest degree in the denominator equal to -3</em>

In all answers the numerator and the denominator have the same highest degree

Lets look for the coefficients of x up and down to find which one gives quotient of -3

∵ In answer A the quotient is 1 because x up and down have

coefficient 1

∵ In answer B the quotient is $-\frac{1}{3}$ because the coefficient of x

up is 1 and down is -3

∵ In answer D the quotient is -1 because the coefficient of x

up is 3 and down is -3

∵ In answer C the quotient is -3 because the coefficient of x up

is -3 and down is 1

∴ The graph of equation $y=\frac{1-3x}{2+x}$ has a horizontal asymptote at y = -3

3 0

4 years ago