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3 years ago

The cost of a camera decreased from $150 to $65.

1 answer:

7 0

90. The original cost of a camera of a camera is 150 dollars, Now it decreased into 65 dollars. Let’s solve for the percent of decreased in the price of the camera. => 150 = 100% => 65 / 150 = .43 => .43 * 100% = 43%, 65 = 43% of the amount => 100% - 43% = 57% Thus, the price of the camera decreased for about 57% of the original price and now only costs 43% of the original price.

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Students were surveyed about their favorite colors 1/4 of the students preferred read 1/8 of the students preferred blue and 3/5

Elanso [62]

Answer: the number of students that were surveyed is 40

Step-by-step explanation:

Let x = total number of students that were surveyed about their favorite colors

1/4 of the students preferred red.

This means that the number of students that preferred red is 1/4 × x = x/4

1/8 of the students preferred blue.

This means that the number of students that preferred blue is 1/8 × x = x/8

The remaining number of students will be the total number of students - the sum of the number of students that preferred red and the number of students that preferred blue. It becomes

x - (x/4 + x/8) = x - 3x/8 = 5x/8

3/5 of the remaining students were for green. This means that the number of students that preferred green is 3/5 × 5x/8 = 3x/8

if 15 students prefer green, then

3x/8 = 15

3x = 120

x = 120/3 = 40 students

5 0

3 years ago

6=x/4-8 for x what equation do you get after adding 8 to each side

Lena [83]

Answer:

After adding 8 you get 14 = x/4.

Step-by-step explanation:

6=x/4-8 Add 8 to both sides:

6 + 8 = x/4 - 8 + 8

14 = x/4

x = 4*14

x = 56.

6 0

3 years ago

Four research teams each used a different method to collect data on how fast a new strain of maize sprouts. Assume that they all

Westkost [7]

Confidence Level: 95%; Confidence Interval: 44 to 46

5 0

3 years ago

Read 2 more answers

Find the complex fourth roots of 81(cos(3pi/8) + i sin(3pi/8))

BartSMP [9]

By using De Moivre's theorem:

If we have the complex number ⇒ z = a ( cos θ + i sin θ)
∴ $\sqrt[n]{z} = \sqrt[n]{a} \ (cos \ \frac{\theta + 360K}{n} + i \ sin \ \frac{\theta +360k}{n} )$
k= 0, 1 , 2, ..... , (n-1)

For The given complex number ⇒ z = 81(cos(3π/8) + i sin(3π/8))


Part (A) find the modulus for all of the fourth roots

∴ The modulus of the given complex number = l z l = 81

∴ The modulus of the fourth root = $\sqrt[4]{z} = \sqrt[4]{81} = 3$

Part (b) find the angle for each of the four roots

The angle of the given complex number = $\frac{3 \pi}{8}$
There is four roots and the angle between each root = $\frac{2 \pi}{4} = \frac{\pi}{2}$
The angle of the first root = $\frac{ \frac{3 \pi}{8} }{4} = \frac{3 \pi}{32}$
The angle of the second root = $\frac{3\pi}{32} + \frac{\pi}{2} = \frac{19\pi}{32}$
The angle of the third root = $\frac{19\pi}{32} + \frac{\pi}{2} = \frac{35\pi}{32}$
The angle of the fourth root = $\frac{35\pi}{32} + \frac{\pi}{2} = \frac{51\pi}{32}$

Part (C): find all of the fourth roots of this

The first root = $z_{1} = 3 ( cos \ \frac{3\pi}{32} + i \ sin \ \frac{3\pi}{32})$
The second root = $z_{2} = 3 ( cos \ \frac{19\pi}{32} + i \ sin \ \frac{19\pi}{32})$

The third root = $z_{3} = 3 ( cos \ \frac{35\pi}{32} + i \ sin \ \frac{35\pi}{32})$
The fourth root = $z_{4} = 3 ( cos \ \frac{51\pi}{32} + i \ sin \ \frac{51\pi}{32})$

7 0

3 years ago

95% of the students passed the math final exam. If 200 students take the final, how many students passed? Steps greatly apprecia

Anit [1.1K]

Answer:

190 students

Step-by-step explanation:

Set up a proportion:

95/100 = x/200

Cross multiply:

100x = 19000

Simplify:

x = 190 students

3 0

3 years ago