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3 years ago

REEEEEEEEEEEEEEEEE I need help plz ;-;

Mathematics

2 answers:

kramer3 years ago

7 0

Answer:

C: y=5x; 50

Step-by-step explanation:

Dividing 130 by 5 tells you that they travel 5 feet per second.

So,

y=5x

y=5(10)

Leni [432]3 years ago

6 0

Answer:

Step-by-step explanation:

150 ft in 30 seconds

150/30=5 we have 5 ft per second

in 10 seconds 5*10=50 ft

choice C

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A flower vendor sells roses for 50 cents each. How much does she pay per flower is she makes $6.00 on every twenty dollars worth

Lelu [443]

One rose is 50 cents, so 2 roses cost $1 ( 50 cents x 2).

2 roses per dollar x 20 dollars = 40 total roses sold.

When they sell $20 dollars they make $6, so that means they pay 20-6 = $14 dollars for the 40 roses.

$14 / 40 roses = 0.35 per rose.

She pays 35 cents per rose.

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Explain how you would graph the line containing a slope of –1/5 that goes through the point (1,–4).

Anettt [7]

Slope = -1/5
Coordinate = (1, -4)

We know, y - y1 = m(x - x1)
y + 4 = -1/5 (x - 1)
y + 4 = -1/5x + 1/5
y = -1/5x -19/5

When, x = 1, y = -1/5(1) - 19/5 = -20/5 = -4
x = 2, y = -1/5(2) - 19/5 = -21/5
x = 3, y = -1/5(3) - 19/5 = -22/5

Here, Your Coordinates would be: (0, -4), (1, -21/5), (2, -22/5)
Mark them & draw the lines. Graph is done!

Hope this helps!

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Convert 5.764764764 to a rational expression

NISA [10]

Answer: 5 and 764 over 999

5764 over 9999

5 and 764 over 99

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Step-by-step explanation:

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3 years ago

let sin(θ) =3/5 and tan(y) =12/5 both angels comes from 2 different right trianglesa)find the third side of the two tringles b)

statuscvo [17]

In a right triangle, we haev some trigonometric relationships between the sides and angles. Given an angle, the ratio between the opposite side to the angle by the hypotenuse is the sine of this angle, therefore, the following statement

$\sin (\theta)=\frac{3}{5}$

Describes the following triangle

To find the missing length x, we could use the Pythagorean Theorem. The sum of the squares of the legs is equal to the square of the hypotenuse. From this, we have the following equation

$x^2+3^2=5^2$

Solving for x, we have

$\begin{gathered} x^2+3^2=5^2 \\ x^2+9=25 \\ x^2=25-9 \\ x^2=16 \\ x=\sqrt[]{16} \\ x=4 \end{gathered}$

The missing length of the first triangle is equal to 4.

For the other triangle, instead of a sine we have a tangent relation. Given an angle in a right triangle, its tanget is equal to the ratio between the opposite side and adjacent side.The following expression

$\tan (y)=\frac{12}{5}$

Describes the following triangle

Using the Pythagorean Theorem again, we have

$5^2+12^2=h^2$

Solving for h, we have

$\begin{gathered} 5^2+12^2=h^2 \\ 25+144=h^2 \\ 169=h^2 \\ h=\sqrt[]{169} \\ h=13 \end{gathered}$

The missing side measure is equal to 13.

Now that we have all sides of both triangles, we can construct any trigonometric relation for those angles.

The sine is the ratio between the opposite side and the hypotenuse, and the cosine is the ratio between the adjacent side and the hypotenuse, therefore, we have the following relations for our angles

$\begin{gathered} \sin (\theta)=\frac{3}{5} \\ \cos (\theta)=\frac{4}{5} \\ \sin (y)=\frac{12}{13} \\ \cos (y)=\frac{5}{13} \end{gathered}$

To calculate the sine and cosine of the sum

$\begin{gathered} \sin (\theta+y) \\ \cos (\theta+y) \end{gathered}$

We can use the following identities

$\begin{gathered} \sin (A+B)=\sin A\cos B+\cos A\sin B \\ \cos (A+B)=\cos A\cos B-\sin A\sin B \end{gathered}$

Using those identities in our problem, we're going to have

$\begin{gathered} \sin (\theta+y)=\sin \theta\cos y+\cos \theta\sin y=\frac{3}{5}\cdot\frac{5}{13}+\frac{4}{5}\cdot\frac{12}{13}=\frac{63}{65} \\ \cos (\theta+y)=\cos \theta\cos y-\sin \theta\sin y=\frac{4}{5}\cdot\frac{5}{13}-\frac{3}{5}\cdot\frac{12}{13}=-\frac{16}{65} \end{gathered}$

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1 year ago