Question

What is an equation of the line that passes through the points (-3, 8) and (4, 1)?

Answer 1

Answer:

The equation of the line is:

$y=-x+5$

Step-by-step explanation:

Given the points

• (-3, 8)

• (4, 1)

Finding the slope between the points

$\left(x_1,\:y_1\right)=\left(-3,\:8\right),\:\left(x_2,\:y_2\right)=\left(4,\:1\right)$

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$m=\frac{1-8}{4-\left(-3\right)}$

$m=-1$

Using the point-slope form of the line equation

$y-y_1=m\left(x-x_1\right)$

where m is the slope

substituting the values m = -1 and the point (-3, 8)

$y-y_1=m\left(x-x_1\right)$

$y-8=-1\cdot \left(x-\left(-3\right)\right)$

$y-8=-\left(x+3\right)$

Add 8 to both sides

$y-8+8=-\left(x+3\right)+8$

$y=-x+5$

Therefore, the equation of the line is:

$y=-x+5$