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2 years ago

How would i solve x^2+4x+2x+8

1 answer:

4 0

Simplify step by step

x^2 + 4x + 2x + 8

combine like terms

x^2 + 4x + 2x + 8 = (x^2) + (4x + 2x) + (8)
= x^2 + 6x + 8

Answer: x^2 + 6x + 8

To Factor:

Factor X^2 + 4X + 2X + 8

X^2 + 6X + 8
= (X + 2)(X + 4)

Answer: = (X +2 )(X +4)

Hope this helps!!!!

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Do all numbers have a prime factorization<br>

loris [4]

Answer:

It depends on the numbers

Step-by-step explanation:

Give some examples

5 0

2 years ago

I know its easy but i suck at math pls help

e-lub [12.9K]

Answer:

-6.8125

Step-by-step explanation:

Convert 13/16 to a decimal.

Write -6 down

You get -6.8125.

Hope this helps! If it does, please mark me brainliest, and press thank you to help me. Thank you! ;)

Good luck on whatever you are doing.

3 0

3 years ago

Read 2 more answers

Find the equation of the linear function represented by the table below in slope-intercept form.

Sedaia [141]

Answer:

y=-4x-5

Step-by-step explanation:

The slope of the line is - 4, the equation of line is y=-4x-5

7 0

2 years ago

John playing with his friends a game where you need to get 20 points to win. In the start of the game John lose 10 points and th

zloy xaker [14]

Answer:

Step-by-step explanation:

0 - 10 = -10

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John has 2 points

3 0

3 years ago

What is the sum of a 12-term arithmetic sequence where the last term is 13 and the common difference is -10?

Y_Kistochka [10]

$\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
n=12\\
d=-10\\
a_{12}=13
\end{cases}
\\\\\\
a_{12}=a_1+(12-1)d\implies 13=a_1+(12-1)(-10)
\\\\\\
13=a_1-110\implies \boxed{123=a_1}$

$\bf \\\\
-------------------------------\\\\
\textit{sum of a finite arithmetic sequence}\\\\
S_n=\cfrac{n}{2}(a_1+a_n)\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
a_n=\textit{value of the }n^{th}\ term\\
------------\\
n=12\\
a_1=123\\
a_{12}=13
\end{cases}
\\\\\\
S_{12}=\cfrac{12}{2}(a_1+a_{12})\implies S_{12}=\cfrac{12}{2}(123+13)$

and surely you know how much that is.

6 0

3 years ago