Greatest common factor 16 and 100

zhuklara [117]

(0.7)(0.4)=0.28 because 7×4 is 28 and you just add a 0

4 0

3 years ago

In the book Essentials of Marketing Research, William R. Dillon, Thomas J. Madden, and Neil H. Firtle discuss a research proposa

MakcuM [25]

Answer:

Null hypothesis: $p_{1} = p_{2}$

Alternative hypothesis: $p_{1} \neq p_{2}$

$z=\frac{0.179-0.15}{\sqrt{0.17(1-0.17)(\frac{1}{140}+\frac{1}{60})}}=0.500$

$p_v =2*P(Z>0.500)=0.617$

So the p value is a very low value and using any significance level for example $\alpha=0.05, 0,1,0.15$ always $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the two proportions NOT differs significantly.

Step-by-step explanation:

Data given and notation

$X_{1}=25$ represent the number of homeowners who would buy the security system

$X_{2}=9$ represent the number of renters who would buy the security system

$n_{1}=140$ sample 1

$n_{2}=60$ sample 2

$p_{1}=\frac{25}{140}=0.179$ represent the proportion of homeowners who would buy the security system

$p_{2}=\frac{9}{60}= 0.15$ represent the proportion of renters who would buy the security system

z would represent the statistic (variable of interest)

$p_v$ represent the value for the test (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the two proportions differs , the system of hypothesis would be:

Null hypothesis: $p_{1} = p_{2}$

Alternative hypothesis: $p_{1} \neq p_{2}$

We need to apply a z test to compare proportions, and the statistic is given by:

$z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}$ (1)

Where $\hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{25+9}{140+60}=0.17$

Calculate the statistic

Replacing in formula (1) the values obtained we got this:

$z=\frac{0.179-0.15}{\sqrt{0.17(1-0.17)(\frac{1}{140}+\frac{1}{60})}}=0.500$

Statistical decision

For this case we don't have a significance level provided $\alpha$ , but we can calculate the p value for this test.

Since is a two sided test the p value would be:

$p_v =2*P(Z>0.500)=0.617$

So the p value is a very low value and using any significance level for example $\alpha=0.05, 0,1,0.15$ always $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the two proportions NOT differs significantly.

6 0

3 years ago

PLEASE HELP ME im so lost on this

netineya [11]

Answer:

Step-by-step explanation:

7 0

3 years ago

I need help i dot get it.

gayaneshka [121]

Answer:

the answer is about 8 cuz the answer shows 7.12 if you divide mentally

6 0

3 years ago

Read 2 more answers

The area of a trapezium is 35cm2.find its altitude if the bases is 6cm and 8cm

r-ruslan [8.4K]

Answer: altitude: 5 cm

Explanation:

$\sf \dfrac{1}{2} ( a + b) h = Area \ of \ trapezium$

[ <u>a and b are bases, h is the altitude</u> ]

Here given:

Area = 35

a = 6

b = 8

h = ?

Solve for altitude:

$\sf \rightarrow \sf \dfrac{1}{2} ( 6 + 8) h = 35 \ \ \ \Rightarrow \ \ \ \dfrac{1}{2} ( 14) h = 35 \ \ \ \ \Rightarrow \ \ \ \ 7 h = 35 \ \ \ \ \Rightarrow \ \ h = \dfrac{35}{7} \ = \ 5$

7 0

2 years ago