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harkovskaia [24]
3 years ago
12

Angle x is an acute angle in a triangle. If cos x=4/5, then the sin x=

Mathematics
2 answers:
Pepsi [2]3 years ago
8 0
The answer is 3/5 because u need to find the missing side in order to find sin

vampirchik [111]3 years ago
5 0

Answer:

\bf \sin x =\frac{3}{5}  

Step-by-step explanation:

Angle x is an acute angle in a triangle.

The measure of cosine angle is given to be :

\cos x = \frac{4}{5}

Now, we need to find the measure of the sine angle for the same triangle.

\cos x = \frac{Base}{Hypotenuse}

⇒ Base = 4 units and Hypotenuse = 5 units

So, Length of perpendicular = 3 units ( By using Pythagoras theorem)

\sin x=\frac{Perpendicular}{Hypotenuse}\\\\\implies\bf \sin x =\frac{3}{5}

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Answer:

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Step-by-step explanation:

We see that the two terms share an x, so we can pull that out:

x^3-x=x(x^2-1)

Now notice that we have a difference of squares (x^2-1). Given a difference of squares, a^2-b^2, this can always be factored into (a+b)(a-b). We can use this in this case: x^2-1=(x+1)(x-1).

So, our final factorized form is: x(x+1)(x-1).

Hope this helps!

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खान लाउनको लागि रोजगारी मिलेकै छ क्यारे !

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