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harkovskaia [24]
3 years ago
12

Angle x is an acute angle in a triangle. If cos x=4/5, then the sin x=

Mathematics
2 answers:
Pepsi [2]3 years ago
8 0
The answer is 3/5 because u need to find the missing side in order to find sin

vampirchik [111]3 years ago
5 0

Answer:

\bf \sin x =\frac{3}{5}  

Step-by-step explanation:

Angle x is an acute angle in a triangle.

The measure of cosine angle is given to be :

\cos x = \frac{4}{5}

Now, we need to find the measure of the sine angle for the same triangle.

\cos x = \frac{Base}{Hypotenuse}

⇒ Base = 4 units and Hypotenuse = 5 units

So, Length of perpendicular = 3 units ( By using Pythagoras theorem)

\sin x=\frac{Perpendicular}{Hypotenuse}\\\\\implies\bf \sin x =\frac{3}{5}

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ra1l [238]
The answer should be:
g <( or equal to)200 gal.
7 0
3 years ago
The interior angle of the regular pentagon below measures 108°, and the
mina [271]
The answer is (108) i hope it works
3 0
2 years ago
Two customers went to a post office to buy postcards and large envelopes. Each postcard
astraxan [27]

The right answer is Option A.

Step-by-step explanation:

Let,

x be the postcards

y be the large envelops

According to given statement;

14x+5y=12   Eqn 1

10x+15y=24.80   Eqn 2

Multiplying Eqn 1 by 3;

3(14x+5y=12)\\42x+15y=36\ \ \ Eqn \ 3

Subtracting Eqn 2 from Eqn 3;

(42x+15y)-(10x+15y)=36-24.80\\42x+15y-10x-15y=11.20\\32x=11.20\\

Dividing both sides by 32

\frac{32x}{32}=\frac{11.20}{32}\\x=0.35

Putting x=0.35 in Eqn 1;

14(0.35)+5y=12\\4.90+5y=12\\5y=12-4.90\\5y=7.10

Dividing both sides by 5

\frac{5y}{5}=\frac{7.10}{5}\\y=1.42

Therefore, one large envelope costs $1.42

The right answer is Option A.

Keywords: linear equations, subtraction

Learn more about linear equations at:

  • brainly.com/question/9738996
  • brainly.com/question/10015690

#LearnwithBrainly

4 0
3 years ago
Find the geometric mean of 4 and 12.
vagabundo [1.1K]

Answer:

The Geometric Mean of 4 and 12 is 6.9

Step-by-step explanation:

4 0
2 years ago
Everyone needs to get off of social and help us -_-
JulsSmile [24]
(x+2)(x+8)(x+k)=x^3+9x^2+6x-16

(x^2+10x+16)(x+k)=x^3+9x^2+6x-16

x^3+10x^2+16x+kx^2+10kx+16k=x^3+9x^2+6x-16

kx^2+10kx+16k=-x^2-10x-16

k(x^2+10x+16)=-x^2-10x-16

k=(-x^2-10x-16)/(x^2+10x+16)

k=-1

so the width is (x-1)




7 0
3 years ago
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