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Vlada [557]
3 years ago
9

I need help on this homework

Mathematics
2 answers:
damaskus [11]3 years ago
6 0

Answer:

x-intercepts are (4,0) and (2,0)

user100 [1]3 years ago
3 0

Answer:

(4,0) and (2,0)

Step-by-step explanation:

For an x-intercept, y=0, so now we have:

(x-4)(x-2)=0

Anything multiplied by 0 is 0, so (x-4)=0 and/or (x-2)=0

(x-4)=0

x=4

(x-2)=0

x=2

The x-intercept co-ordinates are: (4,0), (2,0)

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Find the mean of the data in the dot plot below.
ladessa [460]

Answer:

The answer would be, 2.75

Step-by-step explanation:

Add all the numbers up:

0+1+1+2+3+4+5+6=22

Divide the answer by the amount of numbers:

22÷8=2.75

4 0
3 years ago
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(-2 1/2) to the second power
trapecia [35]

Answer:

6.25

Step-by-step explanation:

(-2\frac{1}{2})^2\\\\(-\frac{5}{2} )^2\\\\(\frac{5}{2})^2\\\\\frac{5^2}{2^2}\\\\\frac{25}{4}\\\\\boxed{6\frac{1}{4}}\text{ or } 6.25

Hope this helps.

5 0
3 years ago
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How can 1% of 800 be used to determine 28% of 800? Enter your answers in boxes to correctly complete the statement.
mote1985 [20]

Answer:

1% of 800 is the unit rate, with the unit rate you can find any percent. such as 28%

Step-by-step explanation:

5 0
3 years ago
A proper unbiased coin was tossed 10 times for 3 trials, giving TTHHTHTTHH, TTTTTHHHHH, and THTHHHTTH (T = Tails; H = Heads). Wh
nadya68 [22]
Theoretical probability is what, theoretically, the probability <em>should </em>be, regardless of data. Because there are only two options, the probability for getting heads on each toss should be 50%. For the total thirty tosses, theoretically, the coin <em>should</em> land on heads fifteen times, or five per trial, which is determined solely on the number of options.

Experimental probability is what the probability was based on the given data. In the first trial, head was scored 5 times, or 5/10, or 50%. This was repeated in the second and third trials. So, based purely <em>on the data,</em> the probability of the coin landing on heads was also 50%.

I hope this helps!
~Chrys

5 0
3 years ago
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X-4y=-18 find three points to graph
Alchen [17]
Easy peasy

sub random points for x and solve for y
or solve for y and sum points for x and get y values

some easy points that work most of the time
sup
x=0
y=0


if x=0
0-4y=-18
4y=18
y=9/2
y=4.5
(0,4.5) is one point

if y=0
x-4(0)=-18
x=-18
(-18,0) is aonther

another is
(-5,2)


3 points are
(0,4.5)
(-18,0)
(-5,2)
3 0
3 years ago
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