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Effectus [21]
3 years ago
15

A proper unbiased coin was tossed 10 times for 3 trials, giving TTHHTHTTHH, TTTTTHHHHH, and THTHHHTTH (T = Tails; H = Heads). Wh

at is the difference between the theoretical and experimental probabilities of getting heads?
Mathematics
2 answers:
nadya68 [22]3 years ago
5 0
Theoretical probability is what, theoretically, the probability <em>should </em>be, regardless of data. Because there are only two options, the probability for getting heads on each toss should be 50%. For the total thirty tosses, theoretically, the coin <em>should</em> land on heads fifteen times, or five per trial, which is determined solely on the number of options.

Experimental probability is what the probability was based on the given data. In the first trial, head was scored 5 times, or 5/10, or 50%. This was repeated in the second and third trials. So, based purely <em>on the data,</em> the probability of the coin landing on heads was also 50%.

I hope this helps!
~Chrys

PilotLPTM [1.2K]3 years ago
4 0

Answer:0.5

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

8 0
1 year ago
Simplify 4x + 5×-5y+3y
uysha [10]
4x+5x-5y+3y&#10; \\ 9x-2y
6 0
2 years ago
If graphed in the plane, would the line y=5x-2 pass through the point (4,15)
yulyashka [42]

Answer:

no

Step-by-step explanation:

Using substitution, subs in the points given

(15) = 5(4) - 2

15 = 20 - 2

Because the 2 sides are NOT equal the line would not pass through the point

5 0
3 years ago
Find the distance between the points given.<br> (0.5) and (-5, 0)
Andrew [12]

Answer:

I cant help unless i have workable units (0.5) is not a point

but im guessing that you were trying to say (0,5) in which case its

7.07106781187

its a triangle

5 on one side

5 on the other

solve for the hypotenuse

hypotenuse = \sqrt{50}

hypotenuse = 7.07106781187

I hope this helps!

8 0
3 years ago
Based on the data given in the picture, calculate the area of the car track...
Verizon [17]

Refer to the diagram below. We need to find the areas of the green and blue regions, then subtract to get the area of the orange track only.

The larger green region is composed of a rectangle of dimensions 200 meters by 4+42+4 = 50 meters, along with two semicircles that combine to make a full circle. This circle has radius 25 meters.

The green rectangle has area 200*50 = 10000 square meters. The green semicircles combine to form an area of pi*r^2 = pi*25^2 = 625pi square meters. In total, the full green area is 10000+625pi square meters. I'm leaving things in terms of pi for now. The approximation will come later.

The blue area is the same story, but smaller dimensions. The blue rectangle has dimensions 200 meters by 42 meters, so its area is 200*42 = 8400 square meters. The blue semicircular pieces combine to a circle with area pi*r^2 = pi*21^2 = 441pi square meters. In total, the blue region has area 8400+441pi square meters.

After we figure out the green and blue areas, we subtract to get the orange region's area, which is the area of the track only.

orange area = (green) - (blue)

track area = (10000+625pi) - (8400+441pi)

track area = 10000+625pi - 8400-441pi

track area = (10000-8400) + (625pi - 441pi)

track area = 184pi + 1600 is the exact area in terms of pi

track area = 2178.05304826052 is the approximate area when you use the pi constant built into your calculator. If you use pi = 3.14 instead, then you'll get 2177.76 as the approximate answer. I think its better to use the more accurate version of pi. Of course, be sure to listen/follow your teachers instructions.

4 0
2 years ago
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