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Alenkinab [10]
2 years ago
12

A bucket holds 8 5/8L of water. A third of the eater is poured out and 3/4L of water is poured back in. How many liters of water

are now in the bucket?
Can you also explain how to get the answer (for brainliest) :>
Mathematics
1 answer:
inna [77]2 years ago
6 0

Answer:

9 and a twentyfourth(9 1/24)

Step-by-step explanation:

If a bucket holds 8 5/8 of water and A third is poured out this will call for subtraction. Afterwards, three quarters is poured back in and this will call for addition.

Rather we can di the sum with the BODMAS way

This is where we will get the addition first and subtraction second. I'll illustrate...

WITHOUT BODMAS: 8 5/8-1/3+3/4

WITH BODMAS:8 5/8 +3/4 -1/3

After calculation we come with the conclusion that the answer is 9 1/24

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Ivan

The answer is unreasonable because the value of x is between 2 and 3.The error is : she did not introducing logs in solving the equation.

Step-by-step explanation:

The question is 7^x=95

Here answers is unreasonable because, she can test with powers of seven like;

7²=49

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So this means the value of x lies between 2 and 3, so here answer 11.71 is unreasonable

b) In this case, to solve the equation, introduce logs both sides

7^x=95

log7^x=log95\\\\\\xlog7=log95\\\\\\x=\frac{log95}{log7} \\\\\\x=2.340

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Indices :brainly.com/question/1660321

Keywords :Equation, error

#LearnwithBrainly

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