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xeze [42]
3 years ago
14

Anybody knknow the answer

Mathematics
1 answer:
vesna_86 [32]3 years ago
3 0
Answer: you can 25/12 to get 2.2 round to the nearest hundred
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Determine the next three terms in the following sequence:<br><br> -1, 1/2, -1/4, 1/8,__,__,__,….
matrenka [14]

Answer:

B

Step-by-step explanation:

1 : 2 = 1/2 : 2 = 1/4 : 2 = 1/8 : 2 = 1/16 : 2 = 1/32 : 2= 1/64

4 0
3 years ago
Help me asap please! please answer all 4 questionsss!! thank you very muchhh!!! ​
cupoosta [38]

Answer:

5. DE

6. 6cm

7.20 in

8. DCF

Step-by-step explanation:

7 0
4 years ago
Hey!
noname [10]

Answer:

A. Cylinder + cone

<u>Volume is the sum of volumes:</u>

  • V = Vcon + Vcyl = 1/3πr²h₁ + πr²h₂
  • V = 1/3π*9²*12 + π*9²*120 = 31554.2 cm³

<u>Surface area of cone:</u>

  • A = A=πr(r+√(h₁²+r²)) = π*9(9 + √(9²+12²)) = 678.6 cm²

<u>Surface area of cylinder minus bases:</u>

  • A = 2πrh₂ = 2π*9*120 = 6785.8 cm²

<u>Total surface area:</u>

  • 678.6 + 6785.8 = 7464.4 cm²

-------------------------------------------------

B. Cube+ pyramid

<u>Volume:</u>

  • V = a³ + (1/3)a²h = a³ + (1/3)a²√(l²-(a/2)²)
  • V = 8³ + (1/3)8²√(10²-4²) = 707.5 cm³

<u>Surface area of pyramid:</u>

  • A = a² + 2al = 8² + 2*8*10 = 224 cm²

<u>Surface area of cube minus bases:</u>

  • A = 4a² = 4(8²) = 256 cm²

<u>Total surface area:</u>

  • A = 224 + 256 = 480 cm²
5 0
3 years ago
A rocket is launched from a tower. The height of the rocket, y in feet is related to the time after launch, x in seconds, by the
gizmo_the_mogwai [7]

Step-by-step explanation:

The height of the rocket y in feet is related to the time after launch, x in seconds, by the given equation i.e.

y=-16x^2+165x+78 ......(1)

It is required to find the maximum height reached by the rocket. For maximum height put \dfrac{dy}{dx}=0.

So,

\dfrac{d(-16x^2+165x+78)}{dx}=0\\\\-32x+165=0\\\\32x=165\\\\x=5.15\ s

Put x = 5.15 in equation (1).

y=-16(5.15)^2+165(5.15)+78\\\\y=503.39\ m

So, the maximum height reached by the rocket is 503.39 m.

5 0
3 years ago
A car painting company has determined that the painting time of cars is uniformly distributed between 25 and 105 minutes. What i
Masteriza [31]

Answer:

P=\frac{5}{16}

Step-by-step explanation:

For a uniform distribution we have to:

P (X\leq x) =\frac{x-a}{b-a}   for x∈ (a, b)

P (X\leq x) =0}   for x\leq a

P (X\leq x) =1}   for x\geq b

In this case we have to:

a = 25 min and b = 105 min

We want to find:

P (40 \leq X \leq 65)

Then

P (x_1 \leq X \leq x_2) = P(X \leq x_2) - P(X \leq x_1)

P (x_1 \leq X \leq x_2)= \frac{x_2 -x_1}{b-a}

In this case:

x_2 = 65\\\\x_1=40

Therefore:

P (40 \leq X \leq 65)=\frac{65 -40}{105-25}

P (40 \leq X \leq 65)=\frac{25}{80}

P (40 \leq X \leq 65)=\frac{5}{16}

4 0
3 years ago
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