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3 years ago

If you can answer this question please do it as soon as you can.

Mathematics

1 answer:

miv72 [106K]3 years ago

8 0

9514 1404 393

Answer:

6.045×10^40 ergs
1.8×10^-2 mm

Step-by-step explanation:

A) Your scientific or graphing calculator can tell you the product:

(3.9×10^33 erg/s)(1.55×10^7 s) = 6.045×10^40 ergs

B) 10^2 mm is 100 mm, about 4 inches, so 1.8×10^2 mm is about 7 inches. This is somewhat larger than the diameter of a human hair (and about the same size as the diameter of a human head).

1.8×10^-2 mm = 18 μm is a more reasonable estimate of hair diameter

(The range of hair diameters is reportedly about 17 to 181 μm, so the given dimension is on the low end.)

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Harrison pays $22.36 each month for his phone bill.

Shalnov [3]

Answer:

Step-by-step explanation:

64.93-22.36=42.57

42.57/4.73=9

6 0

3 years ago

Tickets to the college basketball game are $2.50 for students and $3 for general admission. If 54 people attended the last game

Yuki888 [10]

Answer:

28 general admission
26 student

Step-by-step explanation:

Let g represent the number of general admission tickets sold. Then the revenue is ...

3g +2.50(54-g) = 149

.50g = 14 . . . . . . . . . . . subtract 135

g = 14/.5 = 28 . . general admission tickets sold

54-g = 26 . . . . . student tickets sold

8 0

3 years ago

Pls heeeeeeeeeeeeeeeeeeeeeeeeelp

bonufazy [111]

So
Total cost of the workbooks is d
And the number of workbooks is t
Therefore d = 95
95=19t
t=95/19=5
5 workbooks

6 0

3 years ago

There are (2^6)^3• 2^0bacteria in a sample. What is the total number of bacteria in the sample?

Sedaia [141]

Answer:

262,144

Step-by-step explanation:

2^0 = 1

(2^6)^3 = 2^18 = 262,144

5 0

3 years ago

Read 2 more answers

Ten college students were randomly selected. Their grade point averages (GPAs) when they entered the program were between 3.5 a

solong [7]

Answer:

The 95% confidence interval for the true slope is (0.03985, 0.14206).

Step-by-step explanation:

For the regression equation:

$\hat y=\alpha +\hat \beta x$

The (1 - α)% confidence interval for the regression coefficient or slope $(\hat \beta )$ is:

$Ci=\hat \beta \pm t_{\alpha/2, (n-2)}\times SE(\hat \beta )$

The regression equation for current GPA (Y) of students based on their GPA's when entering the program (X) is:

$\hat Y=3.584756+0.090953 X$

The summary of the regression analysis is:

Predictor Coefficient SE t-stat p-value

Constant 3.584756 0.078183 45.85075 5.66 x 10⁻¹¹

Entering GPA 0.090953 0.022162 4.103932 0.003419

The regression coefficient and standard error are:

$\hat \beta = 0.090953\\SE (\hat \beta)=0.022162$

The critical value of t for 95% confidence level and 8 degrees of freedom is:

$t_{\alpha/2, n-2}=t_{0.05/2, 10-2}=t_{0.025, 8}=2.306$

Compute the 95% confidence interval for $(\hat \beta )$ as follows:

$CI=\hat \beta \pm t_{\alpha/2, (n-2)}\times SE(\hat \beta )\\=0.090953\pm 2.306\times 0.022162\\=0.090953\pm 0.051105572\\=(0.039847428, 0.142058572)\\\approx (0.03985, 0.14206)$

Thus, the 95% confidence interval for the true slope is (0.03985, 0.14206).

6 0

3 years ago