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2 years ago

12

Simplify the expression

-%208p%20%7D%5E%7B2%7D%20%29" id="TexFormula1" title=" {9p}^{4} \: x \: ( { - 8p }^{2} )" alt=" {9p}^{4} \: x \: ( { - 8p }^{2} )" align="absmiddle" class="latex-formula">

1 answer:

lions [1.4K]2 years ago

5 0

Answer:

-72p6x

Step-by-step explanation:

From <em>my </em>previous answer to a question similar

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What is 149 times 5. solve and estimate

GenaCL600 [577]

The answer to this problem is 745.

149 * 5 = 745

In the future, you can do this with a calculator.

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3 years ago

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Work out how many litres of water she saves by having a shower instead of a bath

Ber [7]

Water used for shower = 10.6 x 7 = 74.2 liters

Water used for bath = 35 x 120 x 40 = 168 000 cm³ = 168 liters

Difference = 168 - 74.2 = 93.8 liters.

Answer: She saved 93.8 liters of water by showering instead of taking a bath.

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2 years ago

Use the given information to find the exact value of the trigonometric function

eimsori [14]

$\begin{gathered} \csc \theta=-\frac{6}{5} \\ \tan \theta>0 \\ \cos \frac{\theta}{2}=\text{?} \end{gathered}$

Half Angle Formula

$\cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}}$ $\tan \theta>0\text{ and csc}\theta\text{ is negative in the third quadrant}$ $\begin{gathered} \csc \theta=-\frac{6}{5}=\frac{r}{y} \\ x^2+y^2=r^2 \\ x=\pm\sqrt[\square]{r^2-y^2} \\ x=\pm\sqrt[\square]{6^2-(-5)^2} \\ x=\pm\sqrt[\square]{36-25} \\ x=\pm\sqrt[\square]{11} \\ \text{x is negative since the angle is on the 3rd quadrant} \end{gathered}$ $\begin{gathered} \cos \theta=\frac{x}{r}=\frac{-\sqrt[\square]{11}}{6} \\ \cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}} \\ \cos \frac{\theta}{2}is\text{ also negative in the 3rd quadrant} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{1+\frac{-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{\frac{6-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}} \\ \\ \end{gathered}$

Answer:

$\cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}$

Checking:

$\begin{gathered} \frac{\theta}{2}=\cos ^{-1}(-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}) \\ \frac{\theta}{2}=118.22^{\circ} \\ \theta=236.44^{\circ}\text{ (3rd quadrant)} \end{gathered}$

Also,

$\csc \theta=\frac{1}{\sin\theta}=\frac{1}{\sin (236.44)}=-\frac{6}{5}\text{ QED}$

The answer is none of the choices

7 0

8 months ago

Find the equation of the line parallel to the line y = 4x – 2 that passes through the point (1, 5).

Lesechka [4]

Answer:

4x-y+1=0

Step-by-step explanation:

here,given equation of a line id

4x-y-2=0.. eqn(i)

equation of any line parallel to line (i) is

4x-y+k=0...eqn(ii)

since, the line(ii) passes through (1,5)[replacing x=1 and y=5 in eqn(ii), we get]

4*1-5+k=0

or, 4-5+k=0

or,-1+k=0

•°•k=1

substituting the value of k=1 in eqn(ii),

4x-y+1=0 is the required equation of the line.

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2 years ago

Fill in the blank with the phrase that makes the proof statement true.

melamori03 [73]

Answer:

the two angels are bisect each other

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3 years ago