!!!PLEASE HELP WILL GIVE BRAINLIEST EASY!!!

Mathematics

2 answers:

Eduardwww [97]3 years ago

8 0

NUMBER: 17 SQUARE: 289 SQUARE ROOT: 4.123

Hope this helps a little.

dusya [7]3 years ago

6 0

Answer:

a. 4 and 5

Step-by-step explanation:

We are given 17 squared, and are asked on whether which of it is between the following pairs.

Squaring a number always gives it a smaller number since you are trying to find a number times itself to make the number in the square root.

Therefore by this knowledge, a. would be the most reasonable answer, since 17 is quite a small number, squaring it will equal something smaller.

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find the coordinates of the circumcenter of triangle abc. A(0,5) B(-4,5) C(-4,-3) PLEASE HELP IM FAILING AND I WILL GIVE BRAINLI

hodyreva [135]

(-2,1). Hope this helps!

4 0

3 years ago

In a home theater system, the probability that the video components need repair within 1 year is 0.02, the probability that the

earnstyle [38]

Answer:

(a) The probability that at least one of these components will need repair within 1 year is 0.0278.

(b) The probability that exactly one of these component will need repair within 1 year is 0.0277.

Step-by-step explanation:

Denote the events as follows:

A = video components need repair within 1 year

B = electronic components need repair within 1 year

C = audio components need repair within 1 year

The information provided is:

P (A) = 0.02

P (B) = 0.007

P (C) = 0.001

The events A, B and C are independent.

(a)

Compute the probability that at least one of these components will need repair within 1 year as follows:

P (At least 1 component needs repair)

= 1 - P (No component needs repair)

$=1-P(A^{c}\cap B^{c}\cap C^{c})\\=1-[P(A^{c})\times P(B^{c})\times P(C^{c})]\\=1-[(1-0.02)\times (1-0.007)\times (1-0.001)]\\=1-0.97216686\\=0.02783314\\\approx 0.0278$

Thus, the probability that at least one of these components will need repair within 1 year is 0.0278.

(b)

Compute the probability that exactly one of these component will need repair within 1 year as follows:

P (Exactly 1 component needs repair)

= P (A or B or C)

$=P(A\cap B^{c}\cap C^{c})+P(A^{c}\cap B\cap C^{c})+P(A^{c}\cap B^{c}\cap C)\\=[0.02\times (1-0.007)\times (1-0.001)]+[(1-0.02)\times 0.007\times (1-0.001)]\\+[(1-0.02)\times (1-0.007)\times 0.001]\\=0.02766642\\\approx 0.0277$